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Split a large file in n records and skip a particular record

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# 1  
Split a large file in n records and skip a particular record

Hello All,
I have a large file, more than 50,000 lines, and I want to split it in even 5000 records. Which I can do using
sed '1d;$d;' <filename> | awk 'NR%5000==1{x="F"++i;}{print > x}'

Now I need to add one more condition that is not to break the file at 5000th record if the 5000th record starts with "3" i.e. I need to split the file by further reading it until I encounter a record that does not start with 3.

Below is the sample of the huge file.
  100000035900015300007538   172359500000000000AA000000000Y000000000Y00
  100000035900015300007538   172359500000000000AA000000000Y000000000Y00
  100000035900015300007538   1166231200000000000AA000000000Y000000000Y00
  200000035900015300007538   11029684830A   000000000Y000000000Y01YA 
  200000035900015300007538   0127862850000000000000Y000000000Y00YY 
  200000035900015300007538   01282938700000000000AA000000000Y000000000Y00    
  300000035900015300007538   01282938701025828658A   000000000Y000000000Y01   
  300000035900015300007538   1282938700000000000AA000000000Y000000000Y00
  300000035900015300007538   1282938703028860515A   000000000Y000000000Y03   
  100000035900015300007538   172359500000000000AA000000000Y000000000Y00Y     
  100000035900015300007538   172359500000000000AA000000000Y000000000Y00Y        
  200000035900015300007538   1166231201029684830A   000000000Y000000000Y01YA 
  200000035900015300007538   01278628500000000000AA000000000Y000000000Y00YY

Any help is much appreciated.

Last edited by ibmtech; 11-27-2013 at 05:25 PM..
# 2  
Try this, note I've added a close statement as if you get larger files you may run out of open file handles (depending on your OS and awk version):

sed '1d;$d;' <filename> | awk 'NR%5000==1{N++} N&&!/^\s*3/{if(x) close(x);x="F"++i;N=0}{print > x}'

Last edited by Chubler_XL; 11-27-2013 at 08:50 PM.. Reason: Updated to support blanks at front of record
This User Gave Thanks to Chubler_XL For This Post:
# 3  
Thanks 'Chubler',
When I put my actual file name and try to run, I am getting the below.
sed '1d;$d;' fiscal13 | awk 'NR%5==1{N++} N&&!/^\s*3/{if(x) close(x);x="Fa"++i;N=0}{print > x}'
awk: 0602-576 A print or getline function must have a file name.
 The input line number is 1.
 The source line number is 1.

Any help is much appreciated!
# 4  
Try nawk.
# 5  
Is nawk for AIX? I think its for Solaris.

FYI, I am using AIX. (7.1).

# 6  
nawk is available on many systems, but I think I've spotted the error now:

awk 'BEGIN{x="F"++i } NR%5==1{N++} N&&!/^\s*3/{if(x) close(x);x="Fa"++i;N=0}{print > x}'

This User Gave Thanks to Corona688 For This Post:
# 7  
Try :

$ awk 'NR==1 || NR % 5000 == 1 && !/^\s*3/{close(f);f="File_"++i".tmp"}{print >f}' file

Let me know if I missed something.

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