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Print line between two patterns when a certain pattern matched

 
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Old 11-25-2013
Print line between two patterns when a certain pattern matched
Hello Friends,

I need to print lines in between two string when a keyword existed in those lines (keywords like exception, error, failed, not started etc).

for example,

input:
Code:
..
Begin Edr
ab12
ac13
ad14
bc23
exception occured
bd24
cd34
dd44
ee55
ff66
End Edr
Begin Edr
ab12
ac13
ad14
bc23
bd24
cd34
dd44
ee55
ff66
End Edr
..

..

I need the output:

Code:
Begin Edr
ab12
ac13
ad14
bc23
exception occured
bd24
cd34
dd44
ee55
ff66
End Edr

I found this on the net however i don't know how to modify

Code:
Pattern1="string1"
Pattern2="string2"

$ nawk -v p1=$(Pattern1) -v p2=${Pattern2} '{if ($1==p1) i=1}; {if ($1==p2) i=0}; i{print}' file

or
Code:
Pattern1="string1"
Pattern2="string2"

$ nawk -v p1=$(Pattern1) -v p2=${Pattern2} '{if ($1 ~ p1) i=1}; {if ($1 ~ p2) i=0}; i{print}' file

thanks in advance
Kind Regards
 
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