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How to print only the final path of subdirectories?

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# 1  
Old 11-11-2013
How to print only the final path of subdirectories?
Hello, stumped with the find command to show the final path of subdirectories.

Used the command
Code:
find /dir1 -type d

Output:
Code:
/dir1/dirA
/dir1/dirA/dirB
/dir1/dirA/dirB/dirC

Desired output is:
Code:
/dir1/dirA/dirB/dirC

Please help with awk statement or find syntax. Thanks in advance.
# 2  
Old 11-11-2013
Something like this?
Code:
find /dir1 -type d | awk -F'/' '{m=m<NF?NF:m;A[m]=$0}END{print A[m]}'

# 3  
Old 11-11-2013
Untested:
Code:
p=0
out=''
for x in $(find /dir -type d)
do
    c=$(echo $x | tr -dc '/' | wc -c)
    if [ $c -gt $p ]
    then
        p=$c
        out=$x
    fi
done

echo $out

# 4  
Old 11-11-2013
Can there be multiple subdirectories in a directory? If yes, then neither of the foregoing suggestions will work. If no, then there's a simpler alternative:
Code:
find . -depth -type d | head -n1

Regards,
Alister
# 5  
Old 11-11-2013
Show all final directories
Code:
find . -depth -type d |awk -F/ 'NF>=prev {print} {prev=NF}'

Last edited by MadeInGermany; 11-11-2013 at 04:59 PM..
This User Gave Thanks to MadeInGermany For This Post:
Chubler_XL
# 6  
Old 11-11-2013
How about a recursive bash/ksh approach (which would also include paths that contain symbolic links to directories, which are also paths):
Code:
finalp(){
  typeset dir
  for dir in "$1"/*/
  do
    if [ -d "$dir" ]; then
      finalp "${dir%/}"
    else
      printf "%s\n" "${1%/}"
    fi
  done
}

finalp /dir1

Last edited by Scrutinizer; 11-12-2013 at 02:34 AM..
This User Gave Thanks to Scrutinizer For This Post:
Scott
# 7  
Old 11-11-2013
Smoking solution MadeInGermany - Might have to report you for violating rule #15 :wink:
This User Gave Thanks to Chubler_XL For This Post:
Yoda
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