Shell Programming and Scripting

Hi,
I would like to convert epoch time from the logs to readible fromat.
How do I do it within shell?

Thanks!

what OS are you on?

what's the command to do it?

ok.
Here it is:
System Configuration: Sun Microsystems sun4u
Memory size: 512 Megabytes

Aim this module at your perl ie., #!/path/to/your/perl

Code:

#!/usr/bin/perl
# date from time_t seconds since the start of epoch  then.pl
$then = localtime($ARGV[0]); 
print("$then\n");

usage:

Code:

logdate=`then.pl <time since start of epoch>`
echo "$logdate"

Code:

#!/bin/ksh

# here's my current EPOCH time
currentEpoch=$(/usr/bin/truss /usr/bin/date 2>&1 | /usr/bin/awk '/^time/ {print $NF}')

# here we convert EPOCH back to human readable format
back2Human=$(echo "0t${currentEpoch}=Y" | /usr/bin/adb)

echo "date->[$(date)] currentEpoch->[${currentEpoch}] back2Human->[${back2Human}]"

cin2000, "uname -a" will tell you the os.

vger99, I like that procedure to to get the internal time. I'll never use it, mind you. But I like it anyway. Another way which requires root (or at least non-standard) permission: "echo time/D | adb -k" I used to like these adb tricks but since 64 bit kernels started to arrive they are not as much fun. On a 64 bit kernel, you may need: "echo time+4/D | adb -k"

Between the 32/64 bit confusion and the user permission problems, I have started using perl for this stuff: perl -e 'print time, "\n"'.