Shell Programming and Scripting

hi everyone

I am having some n number of files in folder I want delete a file which name has todays date example my file name is 14(todaysdate) when i want transfer files i want to delete that file which name has 14.i want delete only 14 file.need help

thanks
srivsn

use date +%d to form the filename pattern and remove ths files.

hi my specification is
1)i am reading file in folder and i am renaming that file by reading last line of the file
2)whire renaming the file i am concating new file name with todays date
3)after renaming the file i am transfer that file to another remotel ocation
4)after transfer the files i have to delete the old files from the paraent folder

i am able to do all the requirements but i am getting a single file which name has today date i have to delete that one also

all the files transfering and deleting from the parent folder exept the 14(today named file)

and my code is


day=$(date +%d)
for i in `ls -1 BBW*`
do
last=`tail -1 $i`
pat=`expr "$last" : '.*(\(.*\)).*'`
pat=`echo $pat | sed 's/ /_/'`
pat=$pat$day
mv $i $pat
done
#!/usr/bin/sh
ftp -v -n "10.236.2233" << cmd
user "$1" "$2"
cd $3
mput *_*
bye
cmd
pwd
rm -f *_*
exit


please i am very new to sh.script can you modify the code to delete the only one file which name has 14

thank you