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Help shell script to list filename file_path

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# 1  
Old 10-04-2013
Wrench Help shell script to list filename file_path
HI
owner date and time and size of file in a row
shell script to list filename file_path i have tried the below code

Code:
present_dir=`pwd`
dir=`dirname $0`
list=`ls -lrt | awk {'print $9,$3,$6,$7,$8'}` 
size=`du -h`
path=`cd  $dir;pwd;`
printf  "$list" 
printf "$path"
printf " $size"


but im not getting the path for every file and it is not displaying in one rowSmilie
my output should be like:
Code:
filename filepath owner date and time size

it has to list in this way
Last edited by abiram; 10-04-2013 at 07:08 AM.. Reason: Added missing CODE tags
# 2  
Old 10-04-2013
Code:
one=foo
two=bar
three=baz
printf "%s %s %s\n" "$one" "$two" "$three"

# 3  
Old 10-04-2013
You only get the path once because you're only outputting it once. Your $list has multiple lines in it, but they're not joined to the path output (or the size, for that matter).

One approach could be to just use a for loop, similar to:
Code:
for i in *
do
   filesize=$(du -h $i)
   fileinfo=$(ls -l $i | awk '{printf $3,$6,$7,$8}')

   printf "%s %s %s %s\n" $i $filepath $fileinfo $filesize
done

EDIT: Forgot to set $filepath, but you should get the idea...
Last edited by CarloM; 10-04-2013 at 07:47 AM.. Reason: typo
# 4  
Old 10-04-2013
You can try this also

Code:
ls -lrt -h | awk -v a=$PWD 'BEGIN{print "filename\tfilepath\towner\tdate\ttime\tsize"}{print $9,a,$3,$7"-"$6,$8,$5}' OFS=\\t >filelog.dat

if you need full date and time use this

Code:
ls ---full-time -h

Last edited by Akshay Hegde; 10-04-2013 at 07:54 AM..
# 5  
Old 10-04-2013
You may want to try (given statis available on your system):
Code:
stat -c"%n   $PWD    %U      %y      %s" *

This User Gave Thanks to RudiC For This Post:
CarloM
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