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How to Grep than scan line below grep pattern

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# 8  
Old 10-03-2013
Code:
while read line || [ -n "$line" ]; do
	case $line in
		\;*)		continue;;
		*20131002*)	stored=$line;;
		*Voice*)	echo "$stored $line";;
	esac
done < file

Last edited by jethrow; 10-04-2013 at 12:01 AM..
# 9  
Old 10-04-2013
Another awk version
Code:
awk '/20130210/ {p=$0} /Apple/ {print p,$0}' file
20130210154634 Apple
20130210171829 Apple

# 10  
Old 10-04-2013
One more approach
Code:
$ cat t.txt
20130210132030
A
B
C
Banana
20130210142320
D
E
F
Mango
20130210154634
G
H
I
Apple
20130210163415
J
K
L
Mango
20130210171829
M
N
O
Apple

Code:
awk '{p=$0;getline;getline;getline;getline;if($0~/Apple/)printf p"\t"$0"\n";p=$0}' t.txt
20130210154634    Apple
20130210171829    Apple

Last edited by Akshay Hegde; 10-04-2013 at 08:48 AM..
# 11  
Old 10-04-2013
Hi,
Just for fun (work under linux) Smilie
Code:
$ grep '20130210\|Apple' file | uniq -w8 | paste -d' ' - - | grep Apple
20130210132030 Apple
20130210163415 Apple

Regards.
Last edited by disedorgue; 10-04-2013 at 09:59 AM.. Reason: add grep Apple to fix if last line is date
# 12  
Old 10-04-2013
Coming back to the original request, this might fulfill it:
Code:
awk '/^20131002/ {TMP=$0} /^Voice/ {print TMP" "$0}' file
20131002193434+0500 Voice
20131002193439+0500 Voice

# 13  
Old 10-04-2013
Quote:
Originally Posted by RudiC
Coming back to the original request, this might fulfill it:
Code:
awk '/^20131002/ {TMP=$0} /^Voice/ {print TMP" "$0}' file
20131002193434+0500 Voice
20131002193439+0500 Voice

If date not found and Voice found then print Voice...

Regards.
This User Gave Thanks to disedorgue For This Post:
RudiC
# 14  
Old 10-04-2013
Rats, you're right! Try (untested):
Code:
awk '/^20131002/ {TMP=$0} /^Voice/ && TMP {print TMP" "$0; TMP=""}' file

This User Gave Thanks to RudiC For This Post:
disedorgue
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