How to suppress error in following command?


 
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Old 09-29-2013
How to suppress error in following command?

I have a file containing data in multiple columns. The colums are seperated by pipe (|). I need to extract information as below:


Code:
myfile_20130929_781;10;100.00

where myfile.txt is the file name. 10 is the number of records in the file starting with 120 and 100.00 is the sum of 26th field of all lines starting with 120 in the file.

Code:
echo "myfile_20130929_781.txt"";""`grep ^120 myfile_20130929_781.txt | wc -l`"";"`grep ^120 myfile_20130929_781.txt |cut -f26 -d "|" | awk '{ sum+=$1} END {printf ("%0.2f\n", sum/100)}'`

if the file is moved during execution of above script, I am getting following error:


Code:
grep: can't open myfile_20130929_781.txt
grep: can't open myfile_20130929_781.txt
myfile_20130929_781.txt;0;0.00


How do I avoid first two lines and only get the third line as my output?

Thanks
Angshuman

Last edited by Don Cragun; 09-29-2013 at 02:38 PM.. Reason: Add CODE tags.
 
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