Split file depending on Column Value


 
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# 1  
Old 09-28-2013
Split file depending on Column Value

Hi ,

my file look likes below ,

cat file.csv
Code:
12/09/2014,50,5,0,300
12/09/2014, ,5,0,300
12/09/2014,50,,,300

i need to split file , the first one contains values (2nd column is 50 , 3rd and fourth column is null )
the second file contains all others

firstfile
Code:
12/09/2014,50,,,300

secondfile
Code:
12/09/2014,50,5,0,300
12/09/2014, ,5,0,300

# 2  
Old 09-28-2013
Hi,
try:
Code:
$ cat cutsed.sed
/^[^,]\+,[^,]\+,,,/wfirstfile
/^[^,]\+,[^,]\+,,,/!wsecondfile

and launch:
Code:
sed -f cutsed.sed file.csv

# 3  
Old 09-28-2013
Code:
awk -F, '{if ($2=="50" && $3$4=="") {print >"firstfile"} else {print >"secondfile"}}' file.csv

and the sed solution should be
Code:
/^[^,]*,50,,,/wfirstfile
/^[^,]*,50,,,/!wsecondfile


Last edited by MadeInGermany; 09-28-2013 at 06:58 PM..
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