Shell Programming and Scripting

All of the uses of:

Code:

for i in `pipeline`

will set the variable i to the elements in the output from the pipeline split on the spaces and newlines in the output. You need something that will just split on the newlines. If you didn't want to restrict your processing to the oldest ten matching files, you could just use:

Code:

for i in "MDB_Kernel11.1_gwlog_SUN 22_09_2013"*

With the restriction, you could try:

Code:

ls -rt "MDB_Kernel11.1_gwlog_SUN 22_09_2013"* | head -10 | while IFS='' read -r i
do      gzip "$i"
done

but I'm guessing you probably want something like:

Code:

ls -rt "MDB_Kernel11.1_gwlog_SUN 22_09_2013"* | grep -v '.gz$' | head -10 | while IFS='' read -r i
do      gzip "$i"
done

It is working fine with the below command.

Code:

find . -name "MDB_Kernel11.1_gwlog_TUE 24_09_2013*"  -type f | xargs -I xx rm -rf xx