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Hiding child when called in background

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# 1  
Old 09-17-2013
Hiding child when called in background
Hi,
I have 2 scripts, one of which is calling the other in background. I want only the output of the parent script on the
output
Code:
 
parent.ksh 
#!/bin/ksh
set -x
echo "Calling child."
. ./child.ksh & > /dev/null
track_pid=`echo $!`
echo "Child kicked off in the background."
sleep 20
kill -9 $track_pid
echo "Child killed"

Code:
 
child.ksh
#!/bin/ksh
#set -x
while [ 1 -eq 1 ]
do
echo "Child is running"
sleep 5
done

Code:
 
>parent.ksh
Calling child.
Child is running
Child kicked off in the background.
Child is running
Child is running
Child is running
Child Killed

When the parent is executed, I dont want to see the child (which is runing at the background) echo output.
What should be done on the parent script to make the output as below
Code:
 
Calling child.
Child kicked off in the background.
Child Killed

# 2  
Old 09-17-2013
Try:
Code:
(./child.ksh >/dev/null) &

This User Gave Thanks to Scrutinizer For This Post:
midhun19
# 3  
Old 09-17-2013
Quote:
Originally Posted by Scrutinizer
Try:
Code:
(./child.ksh >/dev/null) &

yes its working ...thanks
# 4  
Old 09-17-2013
Don't source the file child.ksh, but execute it (i.e. remove the first dot in the line). Needs to be chmoded to executable, then.
# 5  
Old 09-17-2013
That is right, you can leave out the parentheses..

Code:
./child.ksh >/dev/null &

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