Problems with script to find file names


 
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Top Forums Shell Programming and Scripting Problems with script to find file names
# 1  
Old 09-10-2013
Tools Problems with script to find file names

Have a text file "test-array.txt" with contents below

a23003
b23406
c23506

Tying to read the above file into an array and search for file-names in a directory TEST_DIR ,recursively with the above names in them.

Example: If TEST_DIR has a files named

xyxa_a23003_test.sql, b23406_test_file.pdc , test_file_c23506.spp

then the script should echo the file names and echo *** error **** else if no files are found then do nothing.



Here is what I have :

Code:
#!/bin/bash
FILE14=test-array.txt
ARRAY14=( $(<"$FILE14") )
for  (( i=0; i<${#ARRAY14[@]}; i++ )); do
if
find TWServer/. -name '${ARRAY14[i]}' &> /dev/null; then
    echo ${ARRAY14[i]}  
    echo ********Restricted files found in the workspace****Error
  
  
  echo No files found in the workspace
  fi
done

# 2  
Old 09-10-2013
1) Variable names don't expand inside single quotes.
2) You don't need an array.

Code:
while read NAME
do
        find . -name "$NAME" ...
done < inputfile

# 3  
Old 09-10-2013
Sorry .Did not quite understand.New to scripting. Can you please help ..:-(

---------- Post updated at 03:34 PM ---------- Previous update was at 03:25 PM ----------

Does NAME here refer to the test-array.txt?
# 4  
Old 09-10-2013
NAME refers to the variable being read from filename.
# 5  
Old 09-10-2013
As your fields in test_array.txt are only partial names, you need to allow for that in the find command. And, even if no files are found, find returns an exit code of 0, so your if always succeeds. You need to analyse the results further, e.g. with the wc command. Try:
Code:
while read PART
    do
    CNT=$(find . -name "*$PART*" ... | wc -l )
    if [ $CNT -gt 0 ]; then ....; else; fi
    done < test_array.txt

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