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If else condition inside for loop of awk command in UNIX shell scripting

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# 1  
Old 09-01-2013
If else condition inside for loop of awk command in UNIX shell scripting
Hi ,
Please excuse me for opening a new thread i am unable to find out the syntax error
in my if else condition inside for loop in awk command ,
my actual aim is to print formatted html td tag when if condition (True) having string as "failed",
could anyone please advise what is the right syntax for the code.
Code:
awk 'BEGIN{RS="\n";
FS="|";
}
{
print "<TR>";
for (i = 1; i <= NF; i++)
{
if ( "$i" == "failed" )
{print "<TD align=left STYLE="background-color:#FF9933">" $i "</TD>";}
else
{print "<TD>" $i "</TD>";}
}
print "</TR>";
print "\n";
}' test_mail.txt

getting the below error:

Code:
awk: cmd. line:9: {print "<TD align=left STYLE="background-color:#FF9933">" $i "</TD>";}
awk: cmd. line:9:                                               ^ syntax error
awk: cmd. line:15: }
awk: cmd. line:15:  ^ unexpected newline or end of string

Thanks,
Regards,
karthikram
# 2  
Old 09-01-2013
Try escaping the inner double quotes:

Code:
... \"background-color:#FF9933\" ...

otherwise background-color:#FF9933 will be treated as awk code.
This User Gave Thanks to Scott For This Post:
karthikram
# 3  
Old 09-01-2013
Hi Scott,

Thanks it worked.

Thanks,
Regards,
karthikram
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