Shell Programming and Scripting

Hello

I am trying to find how to do the following with awk and other tools.

Find a line in the file where the element 1 is equal to 12345, from the first occurrence, in that line find the element 11 what is equal to and print all lines in file where their element 11 is equal to the value of that line.

Code:

1=12344 2=2222 3=110 4=111 11=2222
1=12345 2=2222 3=110 4=111 11=55
1=125 2=2222 3=110 4=111 11=55
1=12345 2=2222 3=110 4=111 11=54
1=125 2=2222 3=110 4=111 11=55
1=12345 2=2222 3=110 4=111 11=50

So with this input it will find the value of 11 of line 2 (which is 55 because that line's element 1 is 12345) and it will print all lines with element 11=55

Thanks

Moderator's Comments:

Please use code tags when posting data and code samples!

Try also

Code:

awk '$1=="1=12345" {if (!L) L=$NF} L==$NF' file
1=12345 2=2222 3=110 4=111 11=55
1=125 2=2222 3=110 4=111 11=55
1=125 2=2222 3=110 4=111 11=55

Thanks!!!