Shell Programming and Scripting

well i have this xml file here: this file is called filereader.xml
<?xml version="1.0" encoding="UTF-8"?>
<file>
<file1>
<filecopy>/new/test/thefile.txt</filecopy>
<filecopy>/new/test/thefile2.ppt</filecopy>

</file1>
</file>

i need to write the script that search for the Bold text inside the xml without using java. The underlined part is the directory... so the script will first look into the tag--filecopy..then look into a basedirectory which i created called checkdirectory after that it will look into /new/test/ in the tag which is also a directory to locate the file.

Eg. thefile.txt is in checkdir/new/test/thefile.txt
and thefile2 is in checkdir/new/thefile2.txt

i have a code here....but it will only capture file in the tag...it will not look into /new/test folder...can someone help me out?

the coding i have is :
#!/bin/sh

sed -e '/filecopy/ !d' -e 's!<filecopy>\([^<]*\)</filecopy>!\1!' filereader.xml | while read file; do
if [ -f "../checkdir/${file}" ]; then
echo "File exists : ${file}"
else
echo "File not exist : $${file}"
fi
done

exit 0

Where are you running the script from? I can't see anything wrong with it as it stands.

Is that supposed to be two full-stops in the file-test? If you're running it from the directory containing checkdir, then it should be one.

Cheers

Well..i manage to solve the problems now...
by doing this

sed -e '/filecopy/ !d' -e 's!<filecopy>\([^<]*\)</filecopy>!\1!' filereader.xml | while read file; do
file_dir=$checkdir/${file}
if [ -f "$file_dir" ]; then
echo "File exists : $file_dir"
else
echo "File not exist : $file_dir"
fi
done