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awk evaluating a string as a math expression

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# 1  
Old 08-07-2013
awk evaluating a string as a math expression
Hi,
I am writing a script in awk trying to replace strings that are math expressions with their result.
For example, I have a file that looks like this:

5-1
32/8-1
4*12
17+1-3

I would like to get the following output:

4
3
48
15

I tried doing it the following way (using the "bc" unix command):
Get the string into an awk variable and then send it to the shell.

The following line works (without using an input variable).
The outputVariable gets the correct answer "4".
Code:
"echo 5-1 | bc" | getline outputVariable;

So, I tried doing it like this:
Code:
"echo "inputVariable" | bc" | getline outputVariable;

This, of course, does not work.

I tried printing it to a file and then taking the string from a file:
Code:
print inputVariable > "./temp"
"tail -1 ./temp | bc" | getline outputVar

This does not work either.

I am out of ideas.

P.S
I did not come up with any way to transform the string into a math expression that awk can process internally (without going to shell).
Maybe there's a way, and this can be a good solution for me.

Thank you for your help.
# 2  
Old 08-07-2013
Code:
while read line;do echo $(($line));done < infile
4
3
48
15

# 3  
Old 08-07-2013
Quote:
Originally Posted by Jotne
Code:
while read line;do echo $(($line));done < infile
4
3
48
15

Sorry,
I don't understand.
# 4  
Old 08-07-2013
perl solution
Code:
$ cat file
5+1
5*9
6/4
7-1

$ cat file | perl -nle 'print eval($_)'
6
45
1.5
6

# 5  
Old 08-07-2013
Quote:
Originally Posted by rajamadhavan
perl solution
Code:
$ cat file
5+1
5*9
6/4
7-1

$ cat file | perl -nle 'print eval($_)'
6
45
1.5
6

OK guys.
I am sorry, I did not make my question clear enough.
My file does not look so simple, it is more complex.
Here's the real input:

Code:
wire        [32-1:0]       jerry_AWADDR;
wire                       jerry_AWVALID;
wire         [4-1:0]       jerry_AWCACHE;
wire         [4-1:0]       jerry_AWID;
wire         [4-1:0]       jerry_AWLEN;
wire         [2-1:0]       jerry_AWLOCK;
wire         [3-1:0]       jerry_AWPROT;
wire         [3-1:0]       jerry_AWSIZE;
wire         [2-1:0]       jerry_AWBURST;
wire        [64-1:0]       jerry_WDATA;
wire         [4-1:0]       jerry_WID;
wire                       jerry_WLAST;
wire         [8-1:0]       jerry_WSTRB;
wire                       jerry_WVALID;
wire                       jerry_BREADY;

Now, I would like to make it look like this:
Code:
wire        [31:0]       jerry_AWADDR;
wire                       jerry_AWVALID;
wire         [3:0]       jerry_AWCACHE;
wire         [3:0]       jerry_AWID;
wire         [3:0]       jerry_AWLEN;
wire         [1:0]       jerry_AWLOCK;
wire         [2:0]       jerry_AWPROT;
wire         [2:0]       jerry_AWSIZE;
wire         [1:0]       jerry_AWBURST;
wire        [63:0]       jerry_WDATA;
wire         [3:0]       jerry_WID;
wire                       jerry_WLAST;
wire         [7:0]       jerry_WSTRB;
wire                       jerry_WVALID;
wire                       jerry_BREADY;

I hope this makes it clearer.

Thank you.
# 6  
Old 08-07-2013
This bash script
while read line;do echo $(($line));done < infile
reads the expression from the file, evaluate it and then print the result.
If you give us some clue of what the goal is, we could give more help.
# 7  
Old 08-07-2013
Code:
awk -F "[:[]" '/:/{"echo $(("$2"))"|getline var;$2="[" var ":"}1' OFS= infile

Last edited by rdcwayx; 08-07-2013 at 07:11 AM..
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