Hi,
I am writing a script in awk trying to replace strings that are math expressions with their result.
For example, I have a file that looks like this:
5-1
32/8-1
4*12
17+1-3
I would like to get the following output:
4
3
48
15
I tried doing it the following way (using the "bc" unix command):
Get the string into an awk variable and then send it to the shell.
The following line works (without using an input variable).
The outputVariable gets the correct answer "4".
So, I tried doing it like this:
This, of course, does not work.
I tried printing it to a file and then taking the string from a file:
This does not work either.
I am out of ideas.
P.S
I did not come up with any way to transform the string into a math expression that awk can process internally (without going to shell).
Maybe there's a way, and this can be a good solution for me.
This bash script while read line;do echo $(($line));done < infile
reads the expression from the file, evaluate it and then print the result.
If you give us some clue of what the goal is, we could give more help.
Hi,
I have the following txt file List_With_Duplicates.txt;
a,1,1
b,3,4
c,5,2
d,6,1
e,3,3
f,3,7
When I run the command
awk -F ',' '{if($2==$3){print $1","$2","$3}}' List_With_Duplicates.txt I get the following output;
a,1,1
e,3,3
This works! as I've compared the 2nd & 3rd... (7 Replies)
Hi expert,
I have log :
TOTAL-TIME : 2125264636
DATA-BYTES-DOWN : 3766111307032
DATA-BYTES-UP : 455032157567
DL = (3766111307032/2125264636)/1024 = 1.73
UL = (455032157567/2125264636)/1024 = 0.21
I want the result :
TOTAL = 1.94 ... (4 Replies)
Anyone ever seen this? Someone mentioned this the other day....
If you do, for instance, in korn shell, echo $(5.2+2.5), it gives the result of 6 regardless.
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592;1;Z:\WB\DOCS;/FS3_100G/FILER112/BU/MPS/DOCS;;;;\\FILER112\BUMPS-DOCS\;580,116,544,878 Bytes;656,561 ;77,560
592;2;Z:\WB\FOCUS;/FS3_100G/FILER112/BU/MPS/FOCUS;;;;\\FILER112\BUMPS-FOCUS\;172,430 Bytes;6 ;0 ... (12 Replies)
I am trying to do some math, so that I can compare the average of six numbers to a variable.
Here is what it looks like (note that when I divide really big numbers, it isn't a real number):
$ tail -n 6 named.stats | awk -F\, '{print$1}'
1141804
1140566
1139429
1134210
1084682
895045... (3 Replies)
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data1.txt
Group... (2 Replies)
Hi,
My file has 2 fields and millions of lines.
variableStep chrom=Uextra span=25
201 0.5952
226 0.330693
251 0.121004
276 0.0736858
301 0.0646982
326 0.0736858
401 0.2952
426 0.230693
451 0.221004
476 0.2736858
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Awk seem treat the pattern as regular expression, how can awk search not using regular expression? e.g. just represent for "", not "A" or "a" . I don't want to add backslash . (2 Replies)