I have a script that does log rotation, at 10000k, it will print out the logs as follows:
name.date.0.log(1gb)
name.date.1.log(1gb)
name.date.2.log(200mb) << current log being written to
at midnight it reverts back to : name.date.0.log(size)
I want it to be able to go past date.9.log into double digits like name.date.10.log
Code:
CURRENT_APSLOG=$($FIND $LOGDIR -type f -name "aps_20*.0_0.log" | sort -r | head -1)
CURRENT_APSLOGDATE=$(basename "$(echo $CURRENT_APSLOG | sed -e 's/.0_0.log$//')")
#echo "CURRENT_APSLOG: $CURRENT_APSLOG"
#echo "CURRENT_APSLOGDATE: $CURRENT_APSLOGDATE"
for l in $($FIND $LOGDIR -type f -name "aps_20*.*.log" -a ! -name "${CURRENT_APSLOGDATE}.*.log")
do
#echo "log: $log"
# for backward compat with HP find has no -mmin so use mmin.pl
mmin.pl $l +60
if [ $? -eq 0 ]
then
BASENM=$(basename "$l")
NEWNM=${ARCDIR}/${BASENM}
# move it to the archive directory
mv $l $NEWNM
fi
done
done
I am sure that I just need to copy this snippet over and add a new variable to the current log since it will not match any others...but I am at a loss of exactly how this should be looked at. Any assitance is appreciated. Thanks
This doesn't look like the thing that rotates the logfiles, exactly... It looks for files older than 60 minutes and moves them.
I take it the difficulty is because it sorts alphabetically, rather than by numbers? 1 10 2 3 4 5 6 7 8 9, vs 1 2 3 4 5 6 7 8 9 10?
I think sorting by date with ls would work better than using find and sorting the names.
Code:
# basename should not be needed, because of cd
# the cd will not persist outside the $( )
CURRENT_APSLOG=$( cd $LOGDIR ; ls -t aps_20*.0_0.log | head -n 1)
Well there is a lot more to this script than that snippet...as well as it calls upon a logfunction tha thas subroutines for ziplog, rototate log and other stuff. But I see what you are saying, that's why I am confused on it
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