Printing next two lines from a file after grepping a specific pattern

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07-18-2013

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change in script..

Code:

awk 'c-->0;$0~s{if(b)for(c=b+1;c>1;c--)print r[(NR-c+1)%b];print;c=a}b{r[NR%b]=$0}' b=0 a=2 s="\\\\<ACCOUNT\\\\>" require.txt

vidyadhar85

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07-18-2013

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Try

Code:

awk '/,ACCOUNT,/ {L=3} L-->0' file

Why don't you give a complete and consistent specificaton of your problem in the first place?

RudiC

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