How to find the date of previous day in shell script?

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Old 07-16-2013
How to find the date of previous day in shell script?

Hi Experts,

i am using the below code get the date of previous day.


datestamp=`date '+%Y%m%d'`
yest=$((datestamp -1))
echo $yest

When i execute the code i am getting output as:


What i am trying here is, based on the date passed i am fetching previus day's date.

for example:

If date passed is date = 16/07/2013, i need date of previous day

15/07/2013 but now i am getting output as 20130715, how can i convert this to format 15/07/2013

Thanks in advance.

Last edited by Scott; 07-16-2013 at 03:52 AM.. Reason: Double post. Closed.
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DATETIME.SETDATE(3)							 1						       DATETIME.SETDATE(3)

DateTime::setDate - Sets the date

       Object oriented style

public DateTime DateTime::setDate (int $year, int $month, int $day) DESCRIPTION
Procedural style DateTime date_date_set (DateTime $object, int $year, int $month, int $day) Resets the current date of the DateTime object to a different date. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $year - Year of the date. o $month - Month of the date. o $day - Day of the date. RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. CHANGELOG
+--------+---------------------------------------------------+ |Version | | | | | | | Description | | | | +--------+---------------------------------------------------+ | 5.3.0 | | | | | | | Changed the return value on success from NULL to | | | DateTime. | | | | +--------+---------------------------------------------------+ EXAMPLES
Example #1 DateTime.setDate(3) example Object oriented style <?php $date = new DateTime(); $date->setDate(2001, 2, 3); echo $date->format('Y-m-d'); ?> Procedural style <?php $date = date_create(); date_date_set($date, 2001, 2, 3); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2001-02-03 Example #2 Values exceeding ranges are added to their parent values <?php $date = new DateTime(); $date->setDate(2001, 2, 28); echo $date->format('Y-m-d') . " "; $date->setDate(2001, 2, 29); echo $date->format('Y-m-d') . " "; $date->setDate(2001, 14, 3); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-02-28 2001-03-01 2002-02-03 SEE ALSO
DateTime.setISODate(3), DateTime.setTime(3). PHP Documentation Group DATETIME.SETDATE(3)