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Problem with sub in awk

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# 1  
Old 07-11-2013
Error Problem with sub in awk
Hello, I am trying to run the following code:

Code:
awk '{if( NR>=10 && NR<=2000 ) sub($0,0)}1' infile > outfile

in this data, to turn every line in a 0:
Code:
 2.735369106580736E-002
 6.959182059322828E-002
 4.932889567426600E-001
 1.189073666992422E+000
 1.363209410266462E+000
 9.255017615634271E-001
 4.535840741145356E-001
 2.144666608842262E-001
 1.249991076790470E-001

The problem is there I'm getting this:
Code:
0
0
0
 1.189073666992422E+000
 1.363209410266462E+000
0
0
0
0

For all data it's ignoring lines with E+000, I'm using GNU Awk 3.1.8.

Any idea how I can solve this problem?? Smilie

Thank you,
# 2  
Old 07-11-2013
The syntax of sub function is:
Code:
sub ( regex, replacement, target)

So it should be:
Code:
sub( /.*/, 0, $0 )

Also note that target is an optional argument. If target is not supplied it will use $0 instead.
This User Gave Thanks to Yoda For This Post:
rogeriog.em
# 3  
Old 07-11-2013
Note that if all you want to do is replace every input line with a 0, there is no need for sub():
Code:
awk '{print 0}' infile > outfile
    or
sed 's/.*/0/' infile > outfile
    or
while read -r x
do      echo 0
done < infile > outfile

will all do the job.
This User Gave Thanks to Don Cragun For This Post:
rogeriog.em
# 4  
Old 07-12-2013
Quote:
Originally Posted by Yoda
. . .
Also note that target is an optional argument. If target is not supplied it will use $0 instead.
Which means that his sub($0,0) reads sub($0,0,$0)and should work fine. I'd rather guess it's to do with the E+which in regexes means "one or more occurrences of E", and the + is consumed, so it does no match $0 any more...
Give us evidence by replacing +000 with -000, or use other positive exponents.
This User Gave Thanks to RudiC For This Post:
rogeriog.em
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