Something is not quite right: POSIX on sort options (the group that defines for UNIX OS providers what things have to do to get certification) when sort has the -n option:
Code:
-n
Restrict the sort key to an initial numeric string, consisting of optional <blank> characters, optional minus-sign, and zero or more
digits with an optional radix character
and thousands separators (as defined in the current locale), which shall be sorted by arithmetic value. An empty digit string
shall be treated as zero.
Leading zeros and signs on zeros shall not affect ordering.
In your locale a radix character is the dot (or period). So with almost any modern UNIX/Linux this should work. What makes you think it does not work?
This User Gave Thanks to jim mcnamara For This Post:
Sorry my bad! I am able to figure it out now,
I was trying sorting this values which were in column 5th, However at a point the 4rth and 5th column touching together and it was making one column sort , so the output was not coming right.
Yoda, Don, thanks. Don, You are right, OS X , is correct. and the command is correct. my data file had problem.
Thanks Jim , able to figure it out.
I was trying sort -rnk 5 and the output was not coming as expected:
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1. The problem statement, all variables and given/known data:
Is there a grep commands for numbers w/decimal points
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I have one input file which is delimited by pipe. I want to put decimal points in this input file at particular position in particular column and also get the negative sign (if any) at start of that column.
$ cat Input_file.txt
11|10102693|1|20151202|10263204|20151127|N|0001... (7 Replies)
Dear all,
I have a txt file with only one column which contains p values. My data looks like this:
5.04726976606584e-190
2.94065711152402e-189
2.94065711152402e-189
9.19932135717279e-176
1.09472516659859e-170
1.24974648916809e-170
0.1223974648916
0.9874974648916
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I would like to set decimal point to 16 in the following bash script but it has syntax error at }:
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i am having a varialbe a , which is input to my file
i want to multiply this input with value .43, and assign it to variable b.
i tried it as below:
#!/bin/sh
a=$1
b=`expr $1\*0.43`
echo b=$b
error : expr: non-integer argument
Please tell me , how to do this.
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I have a file full of coordinates of the form:
37.68899917602539 58.07500076293945 57.79100036621094
The numbers don't always have the same number of decimal points. I need to reduce the decimal points of all the numbers (there are 128 rows of 3 numbers) to 2.
I have tried to do this... (2 Replies)
Hi All,
Here is my original string: 192.168.2.1.8088. The target string I want: 192.168.2.1, how can I use awk or sed or other command to get rid of .8088 in the string?
Thanks,
Ray (9 Replies)
Is there a command that sets a variable length?
I have a input of a variable length field but my output for that field needs to be set to 32 char.
Is there such a command?
I am on a sun box running ksh
Thanks (2 Replies)