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UNIX shell script for loop issue

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# 1  
Old 07-05-2013
UNIX shell script for loop issue
Guys,

Please help on the below.

Code:
 sample.prm
 
/u/test/:
 mail=123@gmail.com
 purgedays=30
 zipdays=7
 purgefile=log.gz
 zipfile=log
 
/u/test/:
 mail=123@gmail.com
 purgedays=30
 purgefile=txt.gz
 zipfile=txt
 zipdays=7

Code:
 
sample.cfg
purge_path="/u/test/"
parmfile=sample.prm
log=sample.log

Code:
sample.sh
#!/bin/sh
#here cfg=
. $cfg
 
for VAR in $purge_path    # was $pruge_path
do
   mail_id=`stanzaget ${parm_file} ${VAR} mailid`
   purge_days=`stanzaget ${parm_file} ${VAR} purgedays`
   zip_days=`stanzaget ${parm_file} ${VAR} zipdays`
   purge_file=`stanzaget ${parm_file} ${VAR} purgefile`
   zip_file=`stanzaget ${parm_file} ${VAR} zipfile`
 
   find $VAR -type f -mtime +$zip_days -name "*zip_file" -exec ls -la {} \;
 
   find $VAR -type f -mtime +$purge_days -name "*purge_file" -exec ls -la {} \;
 
done

when the above script runs, its taking the first stanza values from sample.prm.. Its not taking the second stanza since both are same path(/u/test/)
i want both the paths to be looped while the program is running.
Can anyone please help me on this..

Thanks
Moderator's Comments:
Mod Comment This is a duplicate of another thread.
Last edited by Don Cragun; 07-05-2013 at 06:03 AM.. Reason: Closing duplicate thread.
# 2  
Old 07-05-2013
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