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Assinging output of cut command

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# 1  
Old 06-27-2013
Assinging output of cut command
Hi,
I have the files in the following files in a folder
19996587342
19487656550
19534838736
And i need to get the first 6 characters from the abvoe files
so i used the following script
Code:
#!/bin/ksh
 
for i in 19*
 do
  txt= `$i | cut -c -6`
  echo "$txt"
 done

The error is at line no. 5: command not found
Please suggest me .
Thanks
# 2  
Old 06-27-2013
Quote:
Originally Posted by smile689
Hi,
I have the files in the following files in a folder
19996587342
19487656550
19534838736
And i need to get the first 6 characters from the abvoe files
so i used the following script
Code:
#!/bin/ksh
 
for i in 19*
 do
  txt= `echo $i | cut -c -6`
  echo "$txt"
 done

The error is at line no. 5: command not found
Please suggest me .
Thanks
This User Gave Thanks to pamu For This Post:
smile689
# 3  
Old 06-27-2013
What you are doing is to execute the files. You probably need something more like this:-
Code:
#!/bin/ksh
 
for i in 19*
 do
  txt=`cut -c -6 $i`
  echo "$txt"
 done

The cut command will get you the sixth character from the file referred to by $i You will also notice that I have removed the space after the =.


How big are the files? More than one record might give odd results. If you want the sixth character from the first line only, then:-
Code:
#!/bin/ksh
 
for i in 19*
 do
  txt=`head -1 $i | cut -c -6`
  echo "$txt"
 done


I hope that this helps.

Robin
Liverpool/Blackburn
UK
Last edited by rbatte1; 06-27-2013 at 08:33 AM.. Reason: Added section about multiple lines.
This User Gave Thanks to rbatte1 For This Post:
smile689
# 4  
Old 06-27-2013
It worked , Thank You
# 5  
Old 06-27-2013
use echo $i and not $i
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