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Help me with daily monitoring script

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# 15  
Old 06-27-2013
Two things:-
  • Where have the quotes round the file name gone / why are there { and } around the output?
  • We don't think you can get the create time, just the modification time.

Can you post the code as you have it?



Thanks,
Robin
# 16  
Old 06-27-2013
Hi Robin,

Code remains same as we disscussed i.e

Code:
find /usr/IBM/FileNet/BulkUploaderScript/$i/Log/SuccessLog \
\( -newer range_start -a \! -newer range_end \) \
| while read file
do

lines=`wc -l "$file"`
ls -l "$file" | read w x y z d1 d2 d3 rest
echo "File $file has $lines-1 lines and a date of $d1 $d2 $d3"
done


Ouptut :
Code:
File /usr/IBM/FileNet/BulkUploaderScript/LogsFolder/Log/SuccessLog/CSVSuccessLogHIPAACERTS7-6-2013 15-32-18.csv has        4 /usr/IBM/FileNet/BulkUploaderScript/LogsFolder/Log/SuccessLog/CSVSuccessLogHIPAACERTS7-6-2013 15-32-18.csv-1 lines and a date of

I specified {} to tell it is output,don't take that into consideration .Last modification time is also meets the my Dm requirement.

Thanks
Raghav
Last edited by Franklin52; 06-27-2013 at 07:09 AM.. Reason: Please use code tags
# 17  
Old 07-10-2013
Hi,
Code:
do
     lines=`wc -l "$file"`
   ls -l "$file" | read w x y z d1 d2 d3 rest
   echo "File $file has $lines  lines and a date of $d1 $d2 $d3"
done

OUTPUT:
Code:
File /usr/IBM/FileNet/BulkUploaderScript/LogsFolder/Log/SuccessLog/CSVSuccessLog                                                                                        HIPAACERTS7-6-2013 15-32-18.csv has        4 /usr/IBM/FileNet/BulkUploaderScript                                                                                        /LogsFolder/Log/SuccessLog/CSVSuccessLogHIPAACERTS7-6-2013 15-32-18.csv lines                                           and a date of


Could u please modify this so that i can get last modification date and time of the file .
# 18  
Old 07-10-2013
Sorry, I have been away for a while. Smilie

So,
Code:
do
     lines=`wc -l "$file"`
   ls -l "$file" | read w x y z d1 d2 d3 rest
   echo "File $file has $lines  lines and a date of $d1 $d2 $d3"
done

You say it gives the output:-
Code:
File /usr/IBM/FileNet/BulkUploaderScript/LogsFolder/Log/SuccessLog/CSVSuccessLog

.... but I don't see the literal text that should be there. The lines and a date of bit. I'm confused. Smilie



Can you post a section of output from a simple ls -l any_file so I can check the way it will be presented.



Thanks,
Robin
# 19  
Old 07-10-2013
Output of ls -1 :

Code:
File /usr/IBM/FileNet/BulkUploaderScript/LogsFolder/Log/SuccessLog/CSVSuccessLogHIPAACERTS7-6-2013 15-32-18.csv has    4 
/usr/IBM/FileNet/BulkUploaderScript/LogsFolder/Log/SuccessLog/CSVSuccessLogHIPAACERTS7-6-2013 15-32-18.csv lines and a date of

I guess it the problem is with the read line so in print statement it is not printing d1 ,d2,d3.

Code:
ls -l "$file" | read w x y z d1 d2 d3 rest 
echo "File $file has $lines-1 lines and a date of $d1 $d2 $d3"

# 20  
Old 07-10-2013
your $lines output comes out as 4 filename and not what you intended as just 4 ... your ls -l file | read line is not setting any variables either ... you may want to recheck the appropriate lines on the command line before putting them into the script ...
Code:
lines=`wc -l "$file"`   # <-- may be better as lines=`wc -l < $file`

ls -l "$file" | read w x y z d1 d2 d3  # <-- this line is not setting variables

# 21  
Old 07-10-2013
Can we see output from ls -l too. That's a lower case L flag.


Regards,
Robin
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