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Filtering data base on range

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# 1  
Old 06-18-2013
Filtering data based on range in column
Hi All,
I have the file in following format. I need to change column 16 and column 17 for those lines which has atleast one numerical digit in column 2 , with the exception on SUPP1

Input file :
Code:
S00005615|1044|0|0.00|0|0.00| |112|-30|28.1|0|0| |20130331|220.2|2|3|
S00005623|ESSEX|0|0.00|0|0.00| |136|-116|0|0|0| |20130331|40|23|45|
S00005666|2013|0|0.00|0|0.00| |112|-30|28.1|0|0| |20130331|220.2|56|45|
S00005683|NORFO|0|0.00|0|0.00| |112|60.9|0|0|0| |20130331|345.8|32|45|
S00005702|2511|-31.2|0.00|0|0.00| |112|60.9|0|0|0| |20130331|283.4|23|453|
S00005721|SUPP1|0|0.00|0|0.00| |112|28.1|0|0|0| |20130331|280.2|23|12|

Output File :
Code:
S00005615|1044|0|0.00|0|0.00| |112|-30|28.1|0|0| |20130331|220.2|0|0|
S00005623|ESSEX|0|0.00|0|0.00| |136|-116|0|0|0| |20130331|40|23|45|
S00005666|2013|0|0.00|0|0.00| |112|-30|28.1|0|0| |20130331|220.2|0|0|
S00005683|NORFO|0|0.00|0|0.00| |112|60.9|0|0|0| |20130331|345.8|32|45|
S00005702|2511|-31.2|0.00|0|0.00| |112|60.9|0|0|0| |20130331|283.4|0|0|
S00005721|SUPP1|0|0.00|0|0.00| |112|28.1|0|0|0| |20130331|280.2|23|12|

What's the best way o doing this in shell or awk.Any help is really appreciated
Last edited by nua7; 06-18-2013 at 10:20 AM..
# 2  
Old 06-18-2013
Code:
awk -F \| '$2 !~ /SUPP1/ && $2 ~ /[0-9]/{$(NF-1)=$(NF-2)=0}1' OFS="|" file

This User Gave Thanks to pamu For This Post:
nua7
# 3  
Old 06-18-2013
same as Pamu suggested...

awk 'BEGIN{FS=OFS="|"}$2!~/SUPP1/ && $2 ~/[0-9]/{$16=$17=0}1' file
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