Shell Programming and Scripting

hi,
bash is confusing me. it looks so nice when the script is completed, but the way is sometimes very hard...

i want to replace everything between 'P/' and the next '\' with a static string. my regex can occur multiple times in the text.

i think i'm close to it....

new='zzzzz'
example1='P/a1\abc0123\A/BC' -->> 'P/zzzzz\abc0123\A/BC'
example2='A\P/abcABC012\abc012' -->> 'A\P/zzzzz\abc012'
example3='AB\P/aA12\a01ABC\P/01abc\ABC' -->> 'AB\P/zzzzz\a01ABC\P/zzzzz\ABC'

echo ${example1//P\/*\\/$new}

It would be very nice if someone could help me.
Thanks in advance.

That does look very very close.

Code:

$ echo "${example1//P\/*\\/P/asdf\\}"

P/asdf\A/BC

$

This is not what the OP wants, as the \abc0123 string is missing. Unfortunately, I can't right now find a pattern equivalent to the [^\]* regex.

If your sure there is a match this will work (might have to check something matches first:

Code:

echo ${example1%P/*}P/${new}\\${example1#*P/*\\}

Perl is better for non-greedy match

Code:

$ echo $example1 | perl -nle '$test=$_;$test=~s/P\/.+?\\/zzzz/g;print $test;'
zzzzabc0123\A/BC
$ echo $example3 | perl -nle '$test=$_;$test=~s/P\/.+?\\/zzzz/g;print $test;'
AB\zzzza01ABC\zzzzABC