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Check presence of trigger file

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# 1  
Old 06-12-2013
Check presence of trigger file
Hi,
I make a sftp connection successfully.My requirement is the script shall execute only after i find a trigger file(dailyreport.OK.psv) in the remote dir. If the trigger file is not present ,the script should exit else it should continue with the rest of the scripts statements. Below code is having an issue in the if condition. Need help with this.

Code:
sftp samuser@q15server <<END_SCRIPT
if [! -f /common/XPU0/PDS/*OK*] ; then
exit 0
fi
lcd /app/reporting/daily/temp
get /common/XPU0/PDS/*OUT*.psv
quit
END_SCRIPT
sort -u -t'|' -k1,1r /app/reporting/daily/temp/*OUT*.psv
exit 0

Last edited by Scott; 06-12-2013 at 02:04 PM.. Reason: Code tags, not ICode tags
# 2  
Old 06-12-2013
sftp is not shell. It does not have 'if'.

Run sftp to retrieve the file(s), and see if you have it locally.
# 3  
Old 06-12-2013
I tried removing if outside of the sftp and made the below modification. The script is not able to find OK and gives a message as
Code:
sftp> ./test.sh[13]: ![/app/reporting/daily/temp/*OK*]:  not found

My aim is to check the presence of this .OK file .If its present then i execute the rest of the statements else i quit . The script looks like :

Code:
sftp samuser@q15server <<END_SCRIPT
lcd /app/reporting/daily/temp
get /common/XPU0/PDS/*OK*
get /common/XPU0/PDS/*OUT*.psv
quit
END_SCRIPT
if ![/app/reporting/daily/temp/*OK*];then
exit 0
fi
sort -u -t'|' -k1,1r /app/reporting/daily/temp/*OUT*.psv
exit 0

# 4  
Old 06-12-2013
You can't cram an if-statement together like that, spaces are needed around each token.

Also, you need if [ -f filename ] to look for a filename. But it takes one, and only one filename -- not zero, not three, one. So if * finds more than one file that's a syntax error.

Keeping that in mind I'd try this:

Code:
if ls /app/reporting/daily/temp/*OK* 2>/dev/null
then
...
fi

This uses an external utility, ls, so [ ] aren't needed. The point of this is that you can cram multiple files into ls and it's not an error, but if there's zero files, it will be fed the string /app/reporting/daily/temp/*OK* and will return error because that filename doesn't exist.
This User Gave Thanks to Corona688 For This Post:
samrat dutta
# 5  
Old 06-12-2013
Thanks the ls worked Smilie. Incase i do have a specific file and i wish to check , i tried using the following code but it gave a exception

sftp> ./test.sh[13]: ![-f: not found

Code:
if ![-f /app/reporting/daily/temp/abc.OK];then
echo "No ok file"
fi
exit 0

# 6  
Old 06-12-2013
Again, you need spaces around those [ ] , you can't just jam it all together.

Code:
if ! [ -f /app/reporting/daily/temp/abc.OK ] ; then
echo "missing"
fi

This User Gave Thanks to Corona688 For This Post:
samrat dutta
# 7  
Old 06-14-2013
I want to add the total count of actual records which i want to add as a footer at the end. When i execute the script below i get RECORd_COUNT along with the file name .

Code:
sftp samuser@q15server <<END_SCRIPT
lcd /app/reporting/daily/temp
get /common/XPU0/PDS/*OK*
get /common/XPU0/PDS/*OUT*.psv
quit
END_SCRIPT
if ![/app/reporting/daily/temp/*OK*];then
echo "File missing"
exit 0
fi
sort -u -t'|' -k1,1r /app/reporting/daily/temp/*OUT*.psv
COUNT=$( wc -l) /app/reporting/daily/temp/*OUT*.psv
echo "RECORD_COUNT="$COUNT >> /app/reporting/daily/temp/*OUT*.psv
exit 0

Output is
Code:
RECORD_COUNT= 7 /common/pzuz058/XPU0/PDS/final.psv


How can i avoid the file name coming in the out for the record count ?
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