Reading the text file for particular format


 
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# 8  
Old 06-13-2013
I don't see -lt operator anywhere in the code fragment that you posted!

I guess you did not post the complete code. By the way you can set xtrace/verbose and run your code to check what exactly is causing the error:
Code:
#!/bin/bash -xv

# 9  
Old 06-14-2013
Hi Yoda

Below is the shell script

Code:
 
#! /bin/bash
cat "./Myfile" > input
file="input"
sed -i".backup" 's/^#.*$//' $file
sed -i '/^[[:space:]]*$/d' $file
awk '{for(i=2;i<=NF;i++)print $1,$i}' $file  > temp
mv temp $file
while read ip host
do
(( idx++ ))
HOST[$idx]="$host"
IP[$idx]="$ip"
if [ $(ping -q -c 1 -t 1 "$host" |grep PING | grep -Eo '[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}') = "$ip" ]
 then 
  echo "$name PINGS">>pingresults.txt
  else 
  echo "$name doesnot PINGS">>pingresults.txt
 fi
   
done < $file

At line 9 , am getting the
Code:
"[: -lt: unary operator expected"

error for operator which is the if statement and matching the ip with the ping statement output

line 9 is
Code:
 
if [ $(ping -q -c 1 -t 1 "$host" |grep PING | grep -Eo '[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}') = "$ip" ]

# 10  
Old 06-14-2013
Code:
if [ "$(ping -q -c 1 -t 1 "$host" |grep PING | grep -Eo '[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}')" = "$ip" ]

This User Gave Thanks to rajamadhavan For This Post:
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