Shell Programming and Scripting

I have a string in which i need to match a pattern and then i need to delete that line which contains that matching string.
The string is ..

Code:

This is the  given string
//abc/def/IC.5.4.3/test/...

i need to match //abc

I am writing like this

Code:

sed '/^/\/\abc/d'

but it is not giving me the desired result.

Help me out n tell me where i am wrong ?

Regards
Nishant

try..

Code:

 
sed '#//abc#d'

I tried this but its not working.

Close. You have a / in the wrong place. Try changing:

Code:

sed '/^/\/\abc/d'

to

Code:

sed '/^\/\/abc/d'

Note to vidyadhar85:
You can change the delimiter in a substitute command just be using the desired character (other than backslash (\) and <newline>) where the delimiter goes. But in a context address, if you want to use anything other than slash (/) as the delimiter, you need to escape the 1st delimiter with a backslash. So, the sed command to do the above using # as the delimiter would be:

Code:

sed '\#^//abc#d'

With awk

Code:

awk '!/^\/\/abc/'

Code:

awk '$0!~"^//abc/"'