Shell Programming and Scripting

Hi all..

I have a text file which looks like below:

Code:

abcd
efgh
ijkl
(blank space)

I need to remove only the last (blank space) from the file. When I try wc -l the file name,the number of lines coming is 3 only, however blank space is there in the file.

I have tried options like below:

Code:

awk 'NF' file1 > file2

and some others but nothing worked out.

Please help me in solving this issue.

Thanks & Regards,
Sathya V.

try awk /./ file1

This will remove all the blank lines from the file!

Code:

[user@host ~]$ cat file
abcd
efgh
ijkl

[user@host ~]$ sed '$d' file
abcd
efgh
ijkl
[user@host ~]$

hi balajesuri..

your solutions didnt work in my case..

I guess the sample file you used has space in the last line..whereas my file is just a newline..

please suggest.

thanks..
sathya v.

This works for me

Code:

awk NF

Code:

user1@test /tmp [10:5]$ cat b
dsaf
afds
asdf

user1@test /tmp [10:5]$ awk NF b
dsaf
afds
asdf
user1@test /tmp [10:5]$

So does:

Code:

awk '/./'
awk '!/^$/'
sed '/./!d'

No, there is no space on the last line.

Code:

[user@host ~]$ cat -A file
abcd$
efgh$
ijkl$
$
[user@host ~]$

And in fact, sed '$d' file simply deletes the last line regardless of what it is.

As I mentioned in my mail when I take the count of the file, it is giving me the value without the next line. However when I open the file in vi mode the cursor goes till the line 'ijkl'. This is looking strange. Any suggestions regarding the file?