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How to use this position parameter?

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# 1  
Old 06-06-2013
How to use this position parameter?
Hi Gurus,
I want split one huge line file to multiple line, I got code from you guys yesterday.

I want put the code in a script which use two position parameter when run the script.
my code like:

Code:
awk '{for (i=1; i<=length($0); i+=$2) print substr($0, i, $2)}' $1 > $1_split

when I run the script, I type as
Code:
scriptname file_name liine_length

for some reason, the script doesn't pick $2 value, if I hardcode value instead of $2, the script works.
Code:
awk '{for (i=1; i<=length($0); i+=5) print substr($0, i, 5)}' $1 > $1_split

Can anybody help me out this.

Thanks in advance.
# 2  
Old 06-06-2013
Assign it to an awk variable and use it:
Code:
awk -v L=$2 '{for (i=1; i<=length($0); i+=L) print substr($0, i, L)}' $1 > $1_split

Last edited by Yoda; 06-06-2013 at 01:36 PM.. Reason: correction
This User Gave Thanks to Yoda For This Post:
ken6503
# 3  
Old 06-06-2013
maybe you have to do it like this
Code:
awk '{ print var}' var=$2

Yoda beat me by seconds Smilie
You can have variable in front using -v or after code like I do
This User Gave Thanks to Jotne For This Post:
ken6503
# 4  
Old 06-06-2013
Quote:
Originally Posted by Jotne
maybe you have to do it like this
Code:
awk '{ print var}' var=$2

Yoda beat me by seconds Smilie
You can have variable in front using -v or after code like I do
Hi Jotne,
I tried the way you provided, the process was hanging up

Code:
#!/bin/sh
echo "First position para is $1"
echo "Second position para is $2"
awk '{print var}' var=$2

Code:
sh -x splitfile file 4

result:
Code:
+ echo 'First position para is file'
First position para is file
+ echo 'Second position para is 4'
Second position para is 4
+ awk '{print var}' var=4

would you please take a look.

Thank you very much

---------- Post updated at 03:17 PM ---------- Previous update was at 03:15 PM ----------

Quote:
Originally Posted by Yoda
Assign it to an awk variable and use it:
Code:
awk -v L=$2 '{for (i=1; i<=length($0); i+=L) print substr($0, i, L)}' $1 > $1_split

It works fine.
Thank you very much
Smilie
# 5  
Old 06-06-2013
awk needs input or a BEGIN block, it was just an example.
Example Yoda uses has $1 as input file.
# 6  
Old 06-06-2013
Quote:
Originally Posted by Jotne
awk needs input or a BEGIN block, it was just an example.
Example Yoda uses has $1 as input file.
when I run the script I have input position parameter. for example:

Code:
sh script para1 para2

the script like:
Code:
#!/bin/sh
echo "First position para is $1"
echo "Second position para is $2"
awk '{print var}' var=$2

Thanks
# 7  
Old 06-07-2013
Your awk does not hang up, it needs an input file and because it is missing, awk is waiting for input. Also it is best to quote those references to positional shell parameters..
Code:
awk '{print var}' var="$2" "$1"

or like Yoda suggests:
Code:
awk -v L="$2" ....  "$1"[/COLOR]

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