Shell Programming and Scripting

Hi

need help parsing a file.

I have tag fields and values in a file with delimiter |.

sample records from the file listed below

Code:

8=value|9=value|35=value|49=value|56=value|34=value|50=value|48=value|10=value
8=value|9=value|35=value|49=value|56=value|34=value|51=value|48=value|10=value
8=value|9=value|35=value|49=value|56=value|34=value|54=value|48=value|10=value

if i have to extract 49 && 59 tag values from the same line..i am using the below awk program

Code:

nawk -F'|' '{
 for(i=1;i<NF;i++)
 {
  if ( $i~/^49=/ && $i~/^59=/ )
   { x=x+$i; }
 }
print x; x="";
 }
 }' filename

it's working fine as expected.

i am trying to prepare a fileparser script where i can pass args like "TAG=&&TAG=||TAG="

Code:

scriptname "59&&49||34="

is there anyway to form if condition dynamicaly in awk based on tags and condition provided in args list.

please give me some ideas i will take it further from there..

Code:

myvar="&&TAG"
awk -v var="$myvar" '/$49/ ~ var { do something with field 49 == &&TAG} 'infile

Pass shell variables to nawk or awk with -v[awkvarname]=$shellvar

Hi Jim,
Am I correct in assuming that the / characters marked in red above were typos? I don't think they should be there.

Also note that although the standards require conforming implementations of awk to accept -v options and their option-arguments to be accepted in either of the forms:

Code:

-vAwkVarVame=$ShellVarName

and

Code:

-v AwkVarName=$ShellVarName

some buggy implementations (including awk on Mac OS X 10.7.5) won't accept a -v option unless the -v and its option-argument are in separate arguments.