Log Out SSH User in Bash


 
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Old 05-30-2013
Thanks!

Thankyou so much! Helped loads!

I ended up with:

Code:
pass=$(perl -e 'print crypt($ARGV[0], "password")' $2)
sudo /usr/sbin/useradd $1 -s /bin/bash -p $pass -d /home/onlineusers/$1 -m -g onlineusers
sudo /bin/chmod 700 /home/onlineusers/$1
echo -e "\n"
sleep 1800
USERTTY=$(who | awk '$0 ~ user {print $2}' user=$1)
BASHPROC=$(pgrep -t $USERTTY | sed -n 1p)
kill -HUP $BASHPROC
sudo /usr/sbin/userdel -f $1
sudo /bin/rm -rf /home/onlineusers/$1

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php-config(1)							Scripting Language						     php-config(1)

NAME
php-config - get information about PHP configuration and compile options SYNOPSIS
php-config [options] DESCRIPTION
php-config is a simple shell script for obtaining information about installed PHP configuration. OPTIONS
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