Shell Programming and Scripting

Hello,

From the URL

https://www.unix.com/shell-programmin...ariable-2.html

I got a function to remove the directories from a path. but looks like this isnt quite working.. i am also not able to post the comments in the thread as it is closed.

So can anyone help me with this...

Code:

rmpath() #@ remove directory or directories from $PATH {        #@ USAGE: rmpath dir ...     for p in "$@"     do       p=${p%"${p##*[!/]}"} ## remove trailing slashes       case $PATH in           "$p":*) PATH=${PATH#$p:} ;; ## at beginning of PATH           *:"$p") PATH=${PATH%:$p} ;; ## at end of PATH           *:"$p":*) PATH=${PATH%":$p"*}${PATH##*"$p"} ;;       esac     done     export PATH }

Code:

I've done it yesterdy in a ksh script using awk :

Code:

awk -F"/" '{ print $NF} ' < file

file contain the absolute path

basename command can be used too

What's not working? Post input, desired output, error messages or other indicators so we can help!

I am currently the below script in the link. I would like to have a functionality where the directories get
deleted from the $PATH variable of the system.

For Example:

$ echo $PATH

/users/SINLE/:/bin:/usr/bin:/usr/local/bin:/users/smandodd/bin:/sbin


This is the current content of $PATH.

Now i would like to pass the "/usr/bin" as an argument to the function, which
will delete that path from the $PATH variable.some thing like

$./removepath.sh /usr/bin

$echo $PATH

$
/users/SINLE/:/bin:/usr/local/bin:/users/smandodd/bin:/sbin

This functionality is given by the below function.. but for some reason this
isnt working.. ...


https://www.unix.com/shell-programmin...ariable-2.html









rmpath() #@ remove directory or directories from $PATH { #@ USAGE: rmpath dir ... for p in "$@" do p=${p%"${p##*[!/]}"} ## remove trailing slashes case $PATH in "$p":*) PATH=${PATH#$p:} ;; ## at beginning of PATH *:"$p") PATH=${PATH%:$p} ;; ## at end of PATH *:"$p":*) PATH=${PATH%":$p"*}${PATH##*"$p"} ;; esac done export PATH }

---------- Post updated at 09:55 AM ---------- Previous update was at 09:54 AM ----------

[QUOTE=satishkumar432;302814835]I am currently the below script in the link. I would like to have a functionality where the directories get
deleted from the $PATH variable of the system.

For Example:

$ echo $PATH

/users/SINLE/:/bin:/usr/bin:/usr/local/bin:/users/smandodd/bin:/sbin


This is the current content of $PATH.

Now i would like to pass the "/usr/bin" as an argument to the function, which
will delete that path from the $PATH variable.some thing like

$./removepath.sh /usr/bin

$echo $PATH

$
/users/SINLE/:/bin:/usr/local/bin:/users/smandodd/bin:/sbin

This functionality is given by the below function.. but for some reason this
isnt working.. ...

Code:

rmpath() #@ remove directory or directories from $PATH {        #@ USAGE: rmpath dir ...     for p in "$@"
 do       p=${p%"${p##*[!/]}"} ## remove trailing slashes       case $PATH in           "$p":*) PATH=${PATH#$p:} ;; ## at beginning of PATH           *:"$p") PATH=${PATH%:$p} ;; ## at end of PATH           *:"$p":*) PATH=${PATH%":$p"*}${PATH##*"$p"} ;;
      esac     done     export PATH

Try

Code:

PATH=$(echo $PATH | sed "s#^$1:##;s#:$1:#:#;s#:$1\$##")

Thank You..Rudic..

For a timely response...this works as expected... thank you very much.. as a novice to awk and sed i was not able to figure out .... A request.. could you explain.how you explored the sed options..if possible.. Thanks for your time..

Not sure what you mean by "explore the sed options". If you asked to explain: the sed script consists of three s(ubstitute) commands:

Code:

s#^$1:##        -- subst the parameter $1 incl. ":" at start of line with nothing
s#:$1:#:#       -- subst $1 embedded in ":" in the middle with just one ":"
s#:$1\$##       -- subst ":" + $1 at EOL with nothing

sed, in regexes, takes "^" for begin of line, and "$" for end of line.