Shell Programming and Scripting

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100000

seq 0 25 100000

i=0; while [ $i -le 100000 ]; do echo $i; i=`expr $i + 25`; done

A) Start with a shebang line.

0) Zero a file if you want to to save it all. Ignore this line if you don't want a file...

1) Use a "for" loop that starts at 0, ends at 100000 and with a jump of 25.
2) Inside this loop "append" the zeroed file with each iteration. Ignore this line if you don't want a file...
3) Print the result(s) with or without newlines inside the terminal window.

#!/bin/bash
> number.txt ; for n in $( seq 0 25 100000 ) ; do printf "$n\n" >> number.txt ; printf "$n\n" ; done

awk ' BEGIN { for (i = 0; i <= 100000; i=i+25) print i } '