Command prompt argument


 
Thread Tools Search this Thread
Top Forums Shell Programming and Scripting Command prompt argument
# 1  
Old 10-26-2005
Command prompt argument

I am beginner to UNIX, I want to write shell script for
find greatest of three numbers through command prompt. I have written similar code for converting lowercase to uppercase in command prompt.

I am not getting logica how to implement greatest of three numbers through command prompt.
# 2  
Old 10-26-2005
Is this for a homework assignment?
# 3  
Old 10-27-2005
That is for my 1st practical examination,but I solved my problem.

Quote:
Originally Posted by Ygor
Is this for a homework assignment?
Login or Register to Ask a Question

Previous Thread | Next Thread

10 More Discussions You Might Find Interesting

1. UNIX for Beginners Questions & Answers

Command line argument

Hi Guys, I'm trying to work out how to add a command line argument inside single quotes. Would anyone be able to help please as I'm going mad :) I want to be able to place the filename on command line and it then be used in a script but it needs to have quotes surrounding it. Thanks in... (4 Replies)
Discussion started by: mutley2202
4 Replies

2. UNIX for Dummies Questions & Answers

Shell script not working but command works in command prompt

Hi everyone I have a problem with my script If I try directly this command /usr/bin/nice -n 19 mysqldump -u root --password="******" wiki_schneider -c | nice -n 19 gzip -9 > /point_de_montage/$(date '+%Y%m%d')-wiki-db.sql.gz It works But if I simply add this command in a script and... (8 Replies)
Discussion started by: picemma
8 Replies

3. Shell Programming and Scripting

Command prompt

Hi All, Even changing .bash_profile, i am getting only $ as command prompt. My bash profile looks like this. PS1=" $ " stty columns 200 set -o vi if i run bash command and run PS1=" $ " then it is working as expected. $ bash (4 Replies)
Discussion started by: akshu.agni
4 Replies

4. Shell Programming and Scripting

Specify an entire UNIX command as a command line argument

I'm trying to write a bash script called YN that looks like the following YN "Specify a question" "doThis" "doThat" where "doThis" will be executed if the answer is "y", otherwise "doThat". For example YN "Do you want to list the file dog?" "ls -al dog" "" Here's my attempt... (3 Replies)
Discussion started by: LeoKSimon
3 Replies

5. UNIX for Advanced & Expert Users

autosys command(autorep) from command prompt

Hi, I am using AUTOSYS GUI based tool. But I want to get the job status from the UNIX command prompt. 1. I want to execute only autorep command in the UNIX command prompt. If need to execute this command what are the settings need to do that. 2. Is it possible for executing this... (5 Replies)
Discussion started by: onesuri
5 Replies

6. Shell Programming and Scripting

Cannot compare argument in if statement in csh/grep command if argument starts with “-“

If ($argv == “-debug”) then Echo “in loop” Endif But this is not working. If I modify this code and remove “-“, then it works. Similarly I am getting problem using grep command also Grep “-debug” Filename Can someone please help me on how to resolve these... (1 Reply)
Discussion started by: sarbjit
1 Replies

7. Shell Programming and Scripting

assign a command line argument and a unix command to awk variables

Hi , I have a piece of code ...wherein I need to assign the following ... 1) A command line argument to a variable e.g origCount=ARGV 2) A unix command to a variable e.g result=`wc -l testFile.txt` in my awk shell script When I do this : print "origCount" origCount --> I get the... (0 Replies)
Discussion started by: sweta_doshi
0 Replies

8. Windows & DOS: Issues & Discussions

Command Prompt

Hi does anyone know know how to find out the password on a vista pc using command prompt /cmd not change it (1 Reply)
Discussion started by: popo123456789
1 Replies

9. Shell Programming and Scripting

How to get the value in last command line argument???

Say I want to get the value of last command line argument using the value in $# (or some other way if u can suggest) how do I do it?? $"$#" `$"$#"` These don't work :( (4 Replies)
Discussion started by: amit_oddey21
4 Replies

10. SuSE

inconsistent ls command display at the command prompt & running as a cron job

Sir, I using the following commands in a file (part of a bigger script): #!/bin/bash cd /opt/oracle/bin ls -lt | tail -1 | awk '{print $6}' >> /tmp/ramb.out If I run this from the command prompt the result is: 2007-05-16 if I run it as a cron job then... (5 Replies)
Discussion started by: rajranibl
5 Replies
Login or Register to Ask a Question