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awk question: How to print condition of NR & NF together.

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# 1  
Old 05-24-2013
awk question: How to print condition of NR & NF together.
Experts:

Code:
LINE1 :This is line one The FIRST line of the file.
LINE2 :This is line two
LINE3 :This is line three with 8 fileds
LINE4 :This is line four
LINE5 :This is line five
LINE6 :This is line six with 8 fileds

I want to delete line 1, and then process the file and want to print lines with field not equal to 5.


- I dont want to use sed or other tool for deleting first line.

I am trying:

Code:
awk 'NR !=1 && NF~5{print $0}'

but not working.


The output should be:
Code:
LINE3 :This is line three with 8 fileds
LINE6 :This is line six with 8 fileds


Please advise,
# 2  
Old 05-24-2013
Your code was really close, but I don't know why you used regex comparison operator ~
Code:
awk 'NR!=1&&NF!=5' file

This User Gave Thanks to Yoda For This Post:
rveri
# 3  
Old 05-24-2013
Yoda,
Great ..thanks for the quick response, and thanks for the correction.

Code:
awk 'NR!=1&&NF!=5' file

works great!
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