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Grab the contents with in special character

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# 1  
Old 05-21-2013
Grab the contents with in special character
I have a file which contains below kind of lines

Code:
2013-05-21 00:00:03 [call_eod_unprocess] INFO [ sample_filename1.xml ] moved to unprocessed, as [ sample_filename1.xml ] doesn't exist in masklist and modified at 2013-05-20@21:21:21.000000000.
2013-05-21 00:00:03 [call_eod_unprocess] INFO [ sample_filename2.xml ] moved to unprocessed, as [ sample_filename2.xml ] doesn't exist in masklist and modified at 2013-05-20@21:21:21.000000000.

So, my question is how to grab the content between [] very next to the "INFO" one ?
I did something like this
Code:
awk -F"INFO" '{print $NF}' | awk -F"moved" '{print $1}'

which is working fine, but doesn't give feelings to go for it..Does anyone have any other better idea to carry this?

Code:
Output
sample_filename1.xml
sample_filename2.xml

may be the text next to "unprocessed, as [ XXXX ]" is exactly the same as the text next to INFO; but I'm only interested in text which is very next to INFO only.
# 2  
Old 05-21-2013
Code:
awk -F[][] '{print $4}' file
 sample_filename1.xml
 sample_filename2.xml

Edit: Remove leading space
Code:
awk -F[][] '{sub(" ",x,$4);print $4}' file

or
Code:
awk -F"[][ ]" '{print $9}' file

Last edited by Jotne; 05-21-2013 at 07:21 AM..
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