10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hello,
I'm trying to build a small script to store a command into a dynamic variable, and I have trouble assigning the variable.
#!/bin/bash
declare -a var1array=("value1" "value2" "value3")
var1arraylength=${#var1array}
for (( i=1; i<${var1arraylength}+1; i++ ));
do
mkdir... (7 Replies)
Discussion started by: alex2005
7 Replies
2. UNIX for Dummies Questions & Answers
I am trying to create some variables based on the input by the user, say if user entered 3 then 3 variables and if 5 then 5 variables.
I am using a for loop
for (( i=1; i <= $num; i++ ))
do
x="num"
x+=$i
done
When i am using echo $x it will show num1 but now how to create variables... (3 Replies)
Discussion started by: Raj999
3 Replies
3. Shell Programming and Scripting
I have a small program which needs to pass variable dynamically to form the name of a second variable whose value wil be passed on to a third variable.
***************** Program Start ******************
LOC1=/loc1
PAT1IN=/loc2
PAT2IN=/loc3
if ; then
for fpattern in `cat... (5 Replies)
Discussion started by: Cyril Jos
5 Replies
4. Shell Programming and Scripting
Hello,
I have a problem with a bash script, I've been doing recherches but i can't make it work. It is my first time with a dynamic variable and i don't understand how to write it.
#!/bin/bash
USER=BARSPIN
HOTKEYS_PATH="/home/$USER/Documents/bash/tibia/HOTKEYS"
CFG1="A"
CFG2="B"... (5 Replies)
Discussion started by: barspin
5 Replies
5. Shell Programming and Scripting
Hi guys.
i have a requirment as below.
I have a scripts which perform for loop
for i in /backup/logs -- it will give all the logs file
SC_RIO_RWVM_20120413064217303.LOG
SC_RIO_RWXM_20120413064225493.LOG
SC_RIO_RXXM_20120413064233273.LOG
...
do
open script.sh ---- in this file... (3 Replies)
Discussion started by: guddu_12
3 Replies
6. Shell Programming and Scripting
QUERY IN BRIEF
Listing the query in short
#! /bin/csh -f
#say i have invoked the script with two arguments : a1 and 2
set arg = $1 # that means arg = a1
echo "$arg" #it prints a1
#now what i want is:
echo "$a1"
#it will give error message :a1 undefined.
#however what i need is that the... (2 Replies)
Discussion started by: animesharma
2 Replies
7. Shell Programming and Scripting
I need some variable help
TEMP1=Jane
TEMP2=Sue
X=1
eval USER=TEMP${X}
echo $USER
This gives output USER1
I would like to get Jane
I have tried
eval USER='TEMP${X}'
eval USER="TEMP${X}"
eval USER=`TEMP${X}` (3 Replies)
Discussion started by: Jotne
3 Replies
8. Shell Programming and Scripting
I found one post in another site with a solution for my problem
the below solution should explain what I want.
#!/bin/sh
first="one"
second="two"
third="three"
myvar="first"
echo ${!myvar}
But this gives error 'bad substitution'
System info
SunOS sundev2 5.9... (3 Replies)
Discussion started by: johnbach
3 Replies
9. Shell Programming and Scripting
Hi All,
I have the below scenario:
A file test.cfg with three fields>>
DATA1 DATA2 DATA3
In the script I need to assign each of the fields to variables. The number of fields will not be constant (this case we have three). Im trying to do something like this:
NUM=1
OUT_DAT_NO=3
... (4 Replies)
Discussion started by: deepakgang
4 Replies
10. UNIX for Dummies Questions & Answers
Bit of a newbie :D with regard to unix scripting and need some advice. Hopefully someone can help with the following:
I have a predefined set of variables as follows:
AAA_IP_ADD=1.1.1.1
BBB_IP_ADD=2.2.2.2
I have a funnction call which retrieves a value into $SUPPLIER which would be... (3 Replies)
Discussion started by: ronnie_uk
3 Replies