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Grep for the string and then print the next 4 lines

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# 1  
Old 05-16-2013
Grep for the string and then print the next 4 lines
RHEL 5.8

I have a text file like below. I want to grep for a string and then print the next 4 lines including the line with the string I grepped for

For eg:

I want grep for the string HANS and then print the next 4 lines including HANS

Code:
$ cat someText.txt
JOHN
        NATIONALITY: KENYAN
        OCCUPATION : ACCOUNTANT
        AGE                : 35
MARTHA
        NATIONALITY: BRAZILIAN
        OCCUPATION : LAWYER
        AGE                : 25
HANS
        NATIONALITY: GERMAN
        OCCUPATION : ENGINEER
        AGE                : 29
ALEX
        NATIONALITY: CANADIAN
        OCCUPATION : CHARTERED ACCOUNTANT
        AGE                : 45
KRISHNA
        NATIONALITY: INDIAN
        OCCUPATION : RESEARCHER
        AGE                : 35
$
$
$ grep -n HANS someText.txt   ----------> String HANS is in the 9th line
9:HANS

I want the output to be
Code:
HANS
        NATIONALITY: GERMAN
        OCCUPATION : ENGINEER
        AGE                : 29

This User Gave Thanks to omega3 For This Post:
Gangi Reddy
# 2  
Old 05-16-2013
Code:
grep -A3 HANS someText.txt
HANS
        NATIONALITY: GERMAN
        OCCUPATION : ENGINEER
        AGE                : 29

Code:
awk '/HANS/ {print;getline;print;getline;print;getline;print}' someText.txt

These 2 Users Gave Thanks to Jotne For This Post:
Gangi Reddy omega3
# 3  
Old 05-16-2013
sophisticated command would be Smilie

Code:
 
awk 'c-->0;$0~s{if(b)for(c=b+1;c>1;c--)print r[(NR-c+1)%b];print;c=a}b{r[NR%b]=$0}' b=0 a=3 s="HANS" filename

here b means number of lines above the pattern.. a means below and s for pattern
This User Gave Thanks to vidyadhar85 For This Post:
omega3
# 4  
Old 05-16-2013
More simple awk
Code:
awk '/HANS/ {f=4} f>0 {print;--f}' someText.txt

This User Gave Thanks to Jotne For This Post:
omega3
# 5  
Old 05-16-2013
$ grep -A3 Akhil sample.txt
Akhil
Good
better
best
This User Gave Thanks to Gangi Reddy For This Post:
omega3
# 6  
Old 05-16-2013
@Gangi
Same as I have written in post #2


@vidyadhar85
Quote:
awk 'c-->0;$0~s{if(b)for(c=b+1;c>1;c--)print r[(NR-c+1)%b];print;c=a}b{r[NR%b]=$0}' b=0 a=3 s="HANS" filename
=
Code:
grep -A3 -B0 "HANS" filename

PS your line is nearly impossible to understand. Smilie
So I made a version I understand...
Code:
awk '{a[NR]=$0} $0~s {f=NR} END {for (i=f-B;i<=f+A;i++) print a[i]}' B=2 A=3 s="HANS"

Last edited by Jotne; 05-16-2013 at 02:33 PM..
This User Gave Thanks to Jotne For This Post:
omega3
# 7  
Old 05-16-2013
The following identifies the record end by the next matching ^[A-Z]
Code:
awk '/^[A-Z]/ {pr=0} $0~"^"key" *$" {pr=1} pr' key=KRISHNA someText.txt

Further it matches the key at the beginning, so does not misbehave with key=NATION
Probably easier, an exact string match instead of an ERE match:
Code:
awk '/^[A-Z]/ {pr=0} $0==key {pr=1} pr' key=KRISHNA someText.txt

Last edited by MadeInGermany; 05-16-2013 at 02:28 PM..
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