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Move a text to next line in a file

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# 8  
Old 05-14-2013
Quote:
Originally Posted by Yoda
Code:
awk '
        /pkg1\.func1/ {                 # Check if pattern: pkg1.func1 present in current record.
                gsub ("-->", RS)        # Global Substitute "-->" with RS (RS is a special awk variable, by default a newline)
        }
        1                               # 1 == true (if true, the default awk action is to print current record)
' file


Many thanks for this explanation.
It is totally clear now.
# 9  
Old 05-22-2013
Quote:
Originally Posted by Yoda
Code:
awk '
        /pkg1\.func1/ {                 # Check if pattern: pkg1.func1 present in current record.
                gsub ("-->", RS)        # Global Substitute "-->" with RS (RS is a special awk variable, by default a newline)
        }
        1                               # 1 == true (if true, the default awk action is to print current record)
' file


Hi,

I want to do some added functionality in this file.
Now my file will ahve this type of text.

Quote:
An error came (/u01/app/12.csv)
pkg1.func1: 2.detail is loc error-->pkg1.func1: 1.detail is dept error-->
1. and 2. are the number s which will come along with previous message.This number cab be of n digits.

Now I need to arrange the text in teh below way.

Quote:
An error came (/u01/app/12.csv)
pkg1.func1: detail is dept error
pkg1.func1: detail is loc error
Now I have arranged the text as per the numeric value associated with text and replaced the numeric value in final text.

Thanks in advance.
# 10  
Old 05-22-2013
Starting with Yoda's proposal, you may try:
Code:
$ awk     '/pkg1\.func1/  {n = split ($0, TMP, "-->")
                         for (i=1; i<n; i++)    {m = match (TMP[i], /: [0-9]*\./)
                                                 x = substr (TMP[i], RSTART+2, RLENGTH-3) + 0
                                                 sub (/: [0-9]*\./, ": ", TMP[i])
                                                 OutArr[x] = TMP[i]
                                                 if (x > max) max = x
                                                }
                         for (i=1; i<=max; i++)  if (OutArr[i]) print OutArr[i]   
                         delete OutArr
                         max = 0
                         next
                        }
         1
        ' file
An error came (/u01/app/12.csv)
pkg1.func1: detail is dept error
pkg1.func1: detail is loc error

Last edited by RudiC; 05-22-2013 at 08:07 AM..
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