Shell Programming and Scripting

Hi,

I am getting below error in the log file:

<<
01/05/13 23:30:02 Script Start
find: cannot access tu
File name :
01/05/13 23:30:03 no input file found
01/05/13 23:30:03 Script End
>>

Below is the part of shell script which runs once in a week.It tries to find the latest file created in last 5 minutes with name "xyz.prn".If found then it does some processing.

<<

#!/bin/sh
{
mydir=/home/prn/
touch /home/prn/tu
chmod 777 /home/prn/tu

perl -e '$t=time-600; utime $t,$t,"tu"'

i=`find $mydir -xdev -type f -name "xyz.prn" -newer tu -exec ls {} \;;`

echo 'File name : ' $i

if [ -f "$i" ] then
echo " File found : " $i
# does some processing
else
log "no input file found"
fi

log "Script End"
} >> /home/prn/a.sh 2>&1


>>

Kinldy help me to dentify the issue.How can this warning/error avoided?

Thanks in advance

If you want to find file created in last 5 minutes use -mtime in find and what is tu? is it some file if yes it it accessable by user you running the script?

Specify the full path for the file like you did when you created it with touch:

Code:

i=`find $mydir -xdev -type f -name "xyz.prn" -newer /home/prn/tu -exec ls {} \;;`

Edit: The perl part may not be working correctly for the same reason.

Thanks Cero for your reply. I have one doubt that $mydir already contains the path where both files [xyz.prn and tu ] are located.

i=`find $mydir -xdev -type f -name "xyz.prn" -newer tu -exec ls {} \;;`

I may be wrong, i just wanted to bring into your notice this point.

Kindly suggest.