Sorry, but grep is not an option for this. The grep family of utilities doesn't do arithmetic (including numeric comparisons), it matches strings.
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I take it back. There is a way to do it, it is just messy (and you will need to re-engineer a different expression for each value you're trying to compare). What do you mean by field 2? In you example is field 2 supposed to be 12 or 19? Will you ever have negative numbers? For non-zero values, will there ever be a leading 0?
With grep you don't have $2 to specify the second field and once you have the second field you don't have >.
Last edited by Don Cragun; 05-06-2013 at 01:51 PM..
Reason: Need more details.
This User Gave Thanks to Don Cragun For This Post:
grep does not have a way to tokenise the input like awk/perl (it's not built to do so). You can cook a pattern to match all the way until the required field, but then.. you have awk/perl.
grep does not have a way to tokenise the input like awk/perl (it's not built to do so). You can cook a pattern to match all the way until the required field, but then.. you have awk/perl.
---------- Post updated at 02:04 PM ---------- Previous update was at 01:46 PM ----------
sorry guys, i'm having issues with this:
i want to show whichever line has a value of 5 or more. i'm trying to use this:
Code:
egrep "^\| *[0-9]+ *\| *[5-9]+" data
but it doesn't seem to be working.
---------- Post updated at 02:10 PM ---------- Previous update was at 02:04 PM ----------
Quote:
Originally Posted by Don Cragun
Sorry, but grep is not an option for this. The grep family of utilities doesn't do arithmetic (including numeric comparisons), it matches strings.
------------------------
I take it back. There is a way to do it, it is just messy (and you will need to re-engineer a different expression for each value you're trying to compare). What do you mean by field 2? In you example is field 2 supposed to be 12 or 19? Will you ever have negative numbers? For non-zero values, will there ever be a leading 0?
With grep you don't have $2 to specify the second field and once you have the second field you don't have >.
In this example, the 2nd field would be 19. there's not gonna be a negative number.
To match $3 >= 5, followed by "Mailbox" when your field terminator is '|' try:
Code:
egrep '^[|][^|]*[|] *0*([5-9]|[1-9][0-9]).*Mailbox' data
After finding the 2nd "|" on the line it ignores any number of spaces, any number of leading zeros, and then it looks for a single digit that is 5 through 9 or two or more digits starting with 1 through 9.
To match $3 > 20, followed by "Mailbox" try:
Code:
egrep '^[|][^|]*[|] *0*(2[1-9]|[3-9][0-9]|[1-9][0-9]{2}).*Mailbox' data
After finding the 2nd "|" on the line it ignores any number of spaces, any number of leading zeros, and then looks for a two digit string that is 21-29, a two digit string that is 30-99, or a 3 or more digit string that is greater than or equal to 100.
As you can see you'll need to craft the ERE to use to select the numeric values you're trying to match. Hope these examples help.
Last edited by Don Cragun; 05-06-2013 at 04:30 PM..
Reason: fixed tag
please let me know how to construct if then else by comparing two numbers if it is greater than 10000. I need to do some specific task executed.
can you help me out in shell scripting plz. (6 Replies)
Hi, This is my first post.
I have a korn shell script which outputs a select statment to a file. There is only one column and one row which contains a record count of the select statement.
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Hello,
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data:
hello mr smith 400 you all ok?
hello mrs. smith 700 you all ok?
hello mr. everyone 150 you all ok?
hello mr. you all 199 im lad you are ok
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A file
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In my code I am checking to see if a variable that contains a decimal number is greater than 0 in the following manner:
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do something
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command 9.6352 is not found
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Hello all
Im trying to write one liner that will show me results only if the result of the expression is greater then 0
For example:
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find . -name "*.dsp" | xargs grep -c SecurityHandler
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05-06-2013
