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awk to print record not equal specific pattern

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Top Forums Shell Programming and Scripting awk to print record not equal specific pattern
# 8  
Old 05-02-2013
Quote:
Originally Posted by Corona688
Try nawk instead of awk. On some systems, plain awk is very, very old.

nawk not found in AIX
# 9  
Old 05-02-2013
I think there is some confusion. I was merely trying to correct the syntax error in the original post:
Quote:
Originally Posted by arm
I have tried below

Code:
awk '( $1 ~/[12]0/  ||  $2 ~/[12]0 ) && $3 ! ~/130302/ { print $0 }'  my file

I think awk is confused with the digits after 130302XXXXXX !!!!
If you check, OP missed a slash and there was a blank space ! ~ instead of !~.

So this has nothing to do with nawk or primitive awk
This User Gave Thanks to Yoda For This Post:
arm
# 10  
Old 05-02-2013
Lightbulb
Quote:
Originally Posted by arm
how to use "awk" to print any record has pattern not equal ? for example my file has 5 records & I need to get all lines which $1=10 or 20 , $2=10 or 20 and $3 greater than "130302" as it shown :
...
Maybe simply type this in?
Code:
awk '($1=="10" || $1=="20") && ($2=="10" || $2=="20") && $3>"130302" {print}' myfile

Or modify it a bit like this?
Code:
awk '($1=="10" || $1=="20") && ($2=="10" || $2=="20") && $3>="130303" {print}' myfile

Last edited by MadeInGermany; 05-02-2013 at 07:24 PM.. Reason: bulb icon
This User Gave Thanks to MadeInGermany For This Post:
arm
# 11  
Old 05-02-2013
Quote:
can you explain substr ($3, 0, 6) > 130302
Sure, substr is a function that returns a "substring".

$3 - obviously, that's the field to work on.

0 - starting position. Properly, should have been 1, since awk numbers starting from 1 for this particular thing. It does not mind 0, but 1 is the correct lowest starting position.

6 - length of substring to return.

-------------------

! ~ normally needs to be together like !~to work correctly. My gnu awk requires that, anyway.

Hope this helps. Smilie
This User Gave Thanks to hanson44 For This Post:
arm
# 12  
Old 05-06-2013
but how to do that ? I want to Filter out any record dose belong to “263” in $4 and $6 is before 130304 ?

Code:
2    9647701612350         9647701168456         262       23        1303031257462B0300 1303031259182B0300 92        9647701146402  0
5    9647706046060         9647801139306         263       32        1303031255312B0300 1303031259182B0300 227       9647701146402  0
6    9647706046060         9647801139306         263       32        130325255312B0300 1303251259182B0300 227       9647701146402  0
8    9647701612350         9647701168456         22       262        1303111257462B0300 1303111259182B0300 92        9647701146402  0
9    9647701612350         9647701168456         262      700        1303131257462B0300 1303131259182B0300 92        9647701146402  0
10   9647701612350         9647701168456         22       263        1303031257462B0300 1303031259182B0300 92        9647701146402  0
12   9647706046060         9647801139306         263       32        130303255312B0300 1303032259182B0300 227       9647701146402  0

the output must be

Code:
2    9647701612350         9647701168456         262       23        1303031257462B0300 1303031259182B0300 92        9647701146402  0
6    9647706046060         9647801139306         263       32        130325255312B0300 1303251259182B0300 227       9647701146402  0
8    9647701612350         9647701168456         22       262        1303111257462B0300 1303111259182B0300 92        9647701146402  0
9    9647701612350         9647701168456         262      700        1303131257462B0300 1303131259182B0300 92        9647701146402  0
10   9647701612350         9647701168456         22       263        1303031257462B0300 1303031259182B0300 92        9647701146402  0

Last edited by Scott; 05-06-2013 at 09:05 PM.. Reason: Code tags
# 13  
Old 05-06-2013
Quote:
Filter out any record dose belong to “263” in $4 and $6 is before 130304
Here are two equivalent ways:

Code:
$ awk '$4 == 263 && substr ($6, 1, 6) < 130304 { next } { print }' input
2    9647701612350         9647701168456         262       23        1303031257462B0300 1303031259182B0300 92        9647701146402  0
6    9647706046060         9647801139306         263       32        130325255312B0300 1303251259182B0300 227       9647701146402  0
8    9647701612350         9647701168456         22       262        1303111257462B0300 1303111259182B0300 92        9647701146402  0
9    9647701612350         9647701168456         262      700        1303131257462B0300 1303131259182B0300 92        9647701146402  0
10   9647701612350         9647701168456         22       263        1303031257462B0300 1303031259182B0300 92        9647701146402  0

Code:
$ awk '$4 != 263 || substr ($6, 1, 6) >= 130304 { print }' input
2    9647701612350         9647701168456         262       23        1303031257462B0300 1303031259182B0300 92        9647701146402  0
6    9647706046060         9647801139306         263       32        130325255312B0300 1303251259182B0300 227       9647701146402  0
8    9647701612350         9647701168456         22       262        1303111257462B0300 1303111259182B0300 92        9647701146402  0
9    9647701612350         9647701168456         262      700        1303131257462B0300 1303131259182B0300 92        9647701146402  0
10   9647701612350         9647701168456         22       263        1303031257462B0300 1303031259182B0300 92        9647701146402  0

# 14  
Old 05-08-2013
Quote:
Originally Posted by hanson44
Here are two equivalent ways:

Code:
$ awk '$4 == 263 && substr ($6, 1, 6) < 130304 { next } { print }' input
2    9647701612350         9647701168456         262       23        1303031257462B0300 1303031259182B0300 92        9647701146402  0
6    9647706046060         9647801139306         263       32        130325255312B0300 1303251259182B0300 227       9647701146402  0
8    9647701612350         9647701168456         22       262        1303111257462B0300 1303111259182B0300 92        9647701146402  0
9    9647701612350         9647701168456         262      700        1303131257462B0300 1303131259182B0300 92        9647701146402  0
10   9647701612350         9647701168456         22       263        1303031257462B0300 1303031259182B0300 92        9647701146402  0

Code:
$ awk '$4 != 263 || substr ($6, 1, 6) >= 130304 { print }' input
2    9647701612350         9647701168456         262       23        1303031257462B0300 1303031259182B0300 92        9647701146402  0
6    9647706046060         9647801139306         263       32        130325255312B0300 1303251259182B0300 227       9647701146402  0
8    9647701612350         9647701168456         22       262        1303111257462B0300 1303111259182B0300 92        9647701146402  0
9    9647701612350         9647701168456         262      700        1303131257462B0300 1303131259182B0300 92        9647701146402  0
10   9647701612350         9647701168456         22       263        1303031257462B0300 1303031259182B0300 92        9647701146402  0

thanks I manage to solve it using below code , you may want to take a look and tell me whether correct or not ?

Code:
awk !'($4 ~/263/  && $6 <=130304) {print }'  input
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