Get the MAX value out of a column


 
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# 8  
Old 04-25-2013
Quote:
Originally Posted by Jotne
Other variation
Code:
awk '$3==hi' hi=$(awk '$3>n {n=$3} END {print n}' file) file
12      2       30       100
13      2       30       100

Code:
$ cat file
-1 -1 -1 -1
-2 -2 -2 -2
-3 -3 -3 -3
$ awk '$3==hi' hi=$(awk '$3>n {n=$3} END {print n}' file) file

Same bug as Yoda's code.

Regards,
Alister

---------- Post updated at 02:36 AM ---------- Previous update was at 02:20 AM ----------

Quote:
Originally Posted by RudiC
Code:
$ sort -nr -k3,3 file|awk '$3<p{exit} {p=$3}1' 
13      2       30       100
12      2       30       100

To avoid the trap that alister pointed out, if negative values are expected in the file, preset p by adding p=$(getconf INT_MIN) to the end of the command.
That would not work because AWK implements all numbers, including integers, using type double.
Code:
$ getconf INT_MIN; getconf INT_MIN | awk '{print --$0}'
-2147483648
-2147483649

The simplest, correct solution is to just check if it's the first line: NR!=1 && $3<p.

Regards,
Alister
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