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To display 10 lines before and after the error

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# 1  
Old 04-17-2013
To display 10 lines before and after the error
Hi,

I have a huge log file and I wanted to check for the errors which happened on the particular time frame- Since its huge - vi is making difficult for me
So I used the below command to
Code:
grep -i 'ERROR' wls.log | grep 'Apr 8'

which showed there were few errors

Is there some way, we can also get the 10 lines before and after the error?
Thanks in advance!
Last edited by Franklin52; 04-18-2013 at 04:14 AM.. Reason: Please use code tags
# 2  
Old 04-17-2013
Some systems let you use -B with grep to get context, but odds are good you don't have that. you can use an awk script:

Code:
$ cat context.awk
# Recall N lines ago up to 19 lines
function last(N)
{
        if(N>L) return("");
        return(LINE[(L-N)%20]);
}

{ LINE[(++L)%20]=$0 } # Remember line for later

/Apr 8/ && /ERROR/  {
        for(N=10; N>=0; N--) print last(N);
        for(N=1; N<=9; N++) { getline ; print }
}

$ awk -f context.awk logfile

Use nawk on solaris.
Last edited by Corona688; 04-17-2013 at 04:12 PM..
This User Gave Thanks to Corona688 For This Post:
ajothi
# 3  
Old 04-17-2013
Thanks much!! worked perfectly!!
# 4  
Old 04-17-2013
It had a typo in it meaning you might have only got 9 previous lines instead of ten, fixed now... Close enough for government work anyway Smilie
# 5  
Old 04-18-2013
Try also this:
Code:
grep -i -C 10 'ERROR' wls.log

# 6  
Old 04-18-2013
Code:
grep -C 10  "pattern" filename

Last edited by Franklin52; 04-18-2013 at 08:58 AM.. Reason: Please use code tags
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