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Grepping a word from a .xml file dynamically


 
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# 1  
Grepping a word from a .xml file dynamically

Hi

I have the xml file as
Code:
 <Head="Test"  Id="3" >
            <Title="mode" >

I have used the code to grep the words "Test" and "mode" as
Code:
Head=`cat  file.xml | grep "Head" | awk -F "=" '{print $2}' | awk -F " "  '{print $1}'`
 Tilte=`cat file.xml | grep "Title" | awk -F "=" '{print $2}' | awk -F " "  '{print $1}'`

I get the output as
Head="Test"
Tilte="mode"

But i need as
Head=Test
Tilte=mode

I need to avoid the " " from the output..
Please suggest Smilie

Note: The values of xml tags Head and Title are not constant.. They vary according to the application..

Please help
Thanks in advance
# 2  
I think this is what you need:
Code:
$ cat file.xml
 <Head="Test"  Id="3" >
            <Title="mode" >

Code:
$ cat temp.sh
Head=`grep Head file.xml | sed 's/.*Head="\([^"]*\)".*/Head=\1'/`
Title=`grep Title file.xml | sed 's/.*Title="\([^"]*\)".*/Title=\1'/`
echo $Head
echo $Title

Code:
$ ./temp.sh
Head=Test
Title=mode

-------------------------

Another way to get rid of the "" characters, using your existing code, would be to add to the end of your pipeline:
Code:
tr -d '"'

# 3  
If your grep is GNU, just grep is enough:

To get the Head:
Code:
$ grep -oP '(?<=Head=")[^"]*' file
Test

To get the Title:
Code:
$ grep -oP '(?<=Title=")[^"]*' file
mode

Guru.
# 4  
Its better to use $() compare to back tics `` to get value into variable.
You should not use cat with awk and other programs that accept input

Here is a simple solution with awk:
Code:
Head=$(awk -F\" '/Head/ {print $2}' file.xml)
Title=$(awk -F\" '/Title/ {print $2}' file.xml)


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