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awk - help needed please

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# 1  
Old 04-12-2013
awk - help needed please
Hi..

have a file as below, appreciate if someone can help on this


Code:
143|500| 10| 23353 22131 23355 23354 23358 23352 23357 23350 23349 23351| RAID5
213|1008| 9| 22419 22412 221 22413 22414 22416 22417 22415 22418| RAID6
1088|500| 5| 22243 22240 22244 22242 22241| RAID5
322|1200| 12| 22199 22193 22191 22202 22200 22198 22192 22195 22197 22196 22194 22201| RAID5
404|1000| 4| 22132 22133 22131 22134| RAID5
192|300| 3| 22610 22609 22611| RAID5
275|500| 8| 23085 23083 23086 23084 23087 23089 23090 23088| RAID5
22133|1024| 9| 24231 24234 24237 24235 24239 24238 24233 24236 24232| RAID6
.....


How do I grep for "22133" which is in the 4th Column , columns are seperated by "|"
Last edited by Scrutinizer; 04-13-2013 at 04:10 AM.. Reason: code tags
# 2  
Old 04-12-2013
You could use AWK. grep alone can also do it, although the regexp is a bit more complicated. If the entire line does not need to be printed, then a simple cut|grep is also an option.

What have you tried?

Regards,
Alister
# 3  
Old 04-12-2013
Thanks For the quick response, I tried
Code:
awk -F"|" '$4~/22133/'

works, but when do the same for 133 get same results
also
Code:
awk -F"|" '$4=="22133"'

..no luck
Last edited by Scrutinizer; 04-13-2013 at 04:10 AM.. Reason: code tags
# 4  
Old 04-12-2013
Try:
Code:
awk -F'|' '$4~/(^| )22133( |$)/'

# 5  
Old 04-13-2013
My guess is one of the following (you already know one of them) is what you want:
Code:
$ awk -F '|' '$4 ~ /22133/' file
404|1000| 4| 22132 22133 22131 22134| RAID5

Code:
$ awk -F '|' '$4 ~ /\<22133\>/' file
404|1000| 4| 22132 22133 22131 22134| RAID5

Last edited by Scrutinizer; 04-13-2013 at 04:10 AM.. Reason: code tags
# 6  
Old 04-13-2013
Quote:
Originally Posted by hanson44
My guess is one of the following (you already know one of them) is what you want:
Code:
$ awk -F '|' '$4 ~ /22133/' file
404|1000| 4| 22132 22133 22131 22134| RAID5

Code:
$ awk -F '|' '$4 ~ /\<22133\>/' file
404|1000| 4| 22132 22133 22131 22134| RAID5

richard0@rediff already explained in the 3rd message in this thread that he wants a full word match; not the partial match provided by your first awk example.

Some versions of awk allow \< and \> to match start of word and end of word, respectively. But, that behavior is not portable. The only utilities in the POSIX standards and the Single UNIX Specifications that are specified to handle \< and \> this way are the BREs used in searches in ex and vi. Since Richard didn't say what OS or version of awk was being used, I chose not to use these extensions.

The ERE in the awk script I provided should do what was requested with any version of awk (except that /usr/xpg4/bin/awk, /usr/xpg6/bin/awk, or nawk should be used instead of awk on Solaris/SunOS systems).
# 7  
Old 05-03-2013
Hello Don / Hanson,


Thanks for your help...
This Works..
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