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Print one's place for 1 to N times, ksh Perl whatever?

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Top Forums Shell Programming and Scripting Print one's place for 1 to N times, ksh Perl whatever?
# 8  
Old 04-11-2013
Code:
$ n=1;while (( p = n % 10 , n++ < 133 ));do echo -n $p;done;echo
123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012
$

Last edited by DGPickett; 04-11-2013 at 08:18 PM..
# 9  
Old 04-11-2013
Code:
awk 'BEGIN{while(++i<=x)printf i%10}' x=132

--ahamed
# 10  
Old 04-11-2013
Quote:
awk 'BEGIN{while(++i<=x)printf i%10}' x=132
I tried that. Does not work, at least not in gawk, where x does not get initialized until awk starts reading lines.
# 11  
Old 04-12-2013
Quote:
Originally Posted by hanson44
I tried that. Does not work, at least not in gawk, where x does not get initialized until awk starts reading lines.
You are right. Sorry about that. It will not get initialised in the BEGIN block.

--ahamed
# 12  
Old 04-12-2013
No problema. I went through the same exercise, so I had already made exactly the same assumption.
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